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Katarina [22]
3 years ago
9

A car (m = 1302 kg) traveling along a road begins accelerating with a constant acceleration of 1.50 m/s2 in the direction of mot

ion. After traveling 392 m at this acceleration, its speed is 35.0 m/s. Determine the kinetic energy of the car when it began accelerating.
Physics
1 answer:
antiseptic1488 [7]3 years ago
5 0

First we will use the concepts of motion kinetics for which the final speed is defined as shown below,

v_f^2=v_i^2+2as

Here,

v_f= Final velocity

v_i= Initial velocity

a = Acceleration

s = Distance

Replacing,

(35)^2 = v_i^2+2(1.5)(392)

v_i = 7m/s

Using the conservation of energy for kinetic energy we have,

KE = \frac{1}{2}mv_i^2

KE = \frac{1}{2}(1302)(7)^2

KE = 31900J

Therefore the kinetic energy of the car is 31900J

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