Answer:small barrel gun
Explanation:
Given
Muzzle velocity of bullet is greater in short barrel gun as compared to larger barrel gun
acceleration is given by change in velocity with respect to time
In case of short barrel bullet time taken by bullet to reach its muzzle velocity is less therefore acceleration of small barrel bullet is more compared to long barrel bullet.
We have:
s=3,7km (3700m)
u=0
v=26m/s
a=
t=
We look up for a formula to solve for a:
v²=u²+2as u²=0 so
v²=2as
(26m/s)²=2a3700m
676/7400=a
a=0,09m/s²
Answer:
The resistance R stretched of the wire if it is stretched to twice its original length is [Δ(2L) / A ]* 2
Explanation:
Original Resistance R = ΔL / A
Given length is doubled
New length L' = 2L
New Volume is constant, resistivity and density of material is also assumed to be constant
AL = A'L'
AL = A'(2L)
A' = AL / 2L
A' = A / 2
∴ new Resistance R' = ΔL' / A'
= Δ(2L) / A/2
= [Δ(2L) / A ]* 2
Answer:
a) W = 3.87 10⁻⁴ J
, b) P = 3.10 10⁻³ Pa
, c) λ = 671. 6 nm
, d) frequency does not change
, e) Emax = 1.39 C / m and f) Bmax = 4.7 10⁻⁹ T
Explanation:
a) Let's use the concepts of power that is work for the unit of time and work is the change of kinetic energy
P = W / t
An electromagnetic wave has an intensity
I = P / A =
W = P t
W = 258 10⁻³ 1.5 10⁻³
W = 3.87 10⁻⁴ W s
W = 3.87 10⁻⁴ J
b) the radiation pressure is given by the ratio
P = I / c
Where I is the intensity
I = Powers / A
A = π r² = π (d/2)²
I = 258 10⁻³ / π (297.5 10⁻⁶)²
I = 9.29 10 5 W / m²
P = 9.29 10⁵/3 10⁸
P = 3.10 10⁻³ Pa
c) The wavelength when passing a measured of different refractive index changes in the way
λ = λ₀ / n
λ = 900 10⁻⁹ / 1.34
λ = 671.6 10⁻⁹ m
λ = 671. 6 nm
d) when the light strikes a medium creates a forced oscillation in the electrons of the medium, this is a resonance phenomenon, so the frequency does not change
e) The maximum electric field is
I = Emax2 / 2 μ₀ c
Emax = Ra (2 μ₀ c I)
Emax = Ra (2 4 π 10⁻⁷ 3 10⁸ 258 10⁻³)
Emax = 1.39 C / m
f) the elective and magnetic fields are related
c = Emax Bmax
Bmax = Emax / c
Bmax = 1.39 / 3 10⁸
Bmax = 4.7 10⁻⁹ T
