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tatuchka [14]
2 years ago
14

Motion with constant acceleration CER lab report Can someone help!!

Physics
1 answer:
victus00 [196]2 years ago
8 0

Answer:

Fan Speed For Low Position vs Time Graph : The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.

Fan Speed For Medium Position vs Time Graph : The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.

Fan Speed For High Position vs Time Graph: The Graph has a smaller curve then the low and medium speed. Also , the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs .

Explanation: I just finished the lab:)

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nydimaria [60]

The average speed of the car for the entire trip can be calculate by using:

v=\frac{S}{t}

where S is the total distance covered by the car, and t is the total time taken.


The total distance travelled by the car is:

S=80 km+50 km+40 km=170 km

while the total time taken is:

t=1.00 h+0.50 h+0.50 h=2.00 h


so, the average speed of the car is:

v=\frac{S}{t}=\frac{170 km}{2.00 h}=85 km/h


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Water that rises to the surface as a result of upwelling is typically colder and is rich in nutrients. These nutrients “fertilize” surface waters, meaning that these surface waters often have high biological productivity.  Therefore, good fishing grounds typically are found where upwelling is common.

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3 years ago
An amusement park ride consists of a rotating circular platform 8.26 m in diameter from which 10 kg seats are suspended at the e
VashaNatasha [74]

To solve this problem we will begin by finding the necessary and effective distances that act as components of the centripetal and gravity Forces. Later using the same relationships we will find the speed of the body. The second part of the problem will use the equations previously found to find the tension.

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r = \frac{8.26}{2} = 4.13m

And the distance 'd' is

d = lsin\theta

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d = 0.318m

Through the free-body diagram the tension components are given by

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Here we can watch that,

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Dividing both expression we have that,

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Replacing the values,

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Tcos\theta = mg

T = \frac{mg}{cos\theta}

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T = 369.42N

6 0
3 years ago
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vlabodo [156]
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Answer:

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