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crimeas [40]
1 year ago
6

Point charge 3.0 μC is located at x = 0, y = 0.30 m, point charge -3.0 μC is located at x = 0 y = -0.30 m. What are (a)the magni

tude and (b)direction of the total electric force that these charges exert on a third point charge Q = 4.5 μC at x = 0.40 m, y = 0?
Physics
1 answer:
fiasKO [112]1 year ago
4 0

The total electric force that these charges exert on a third point charge is 11.9 N and the direction is towards positive y axis.

<h3>Magnitude of the electric force between the charges</h3>

The force between the first charge and the third charge is calculated as follows;

F₁₃ = kq₁q₃/r₁₃²

F₁₃ = (9 x 10⁹ x 3 x 10⁻⁶ x 4.5 x 10⁻⁶) / (0.1)²

<u>note:</u><em> distance between charge 3.0 μC and Q = 4.5 μC  = 0.4 m - 0.3 m = 0.1 m</em>

F₁₃ = 12.15 N

The force between the second charge and the third charge is calculated as follows;

F₂₃ = kq₂q₃/r₂₃²

F₂₃ = (9 x 10⁹ x -3 x 10⁻⁶ x 4.5 x 10⁻⁶) / (0.7)²

<u>note:</u><em> distance between charge -3.0 μC and Q = 4.5 μC  = 0.4 m - (-0.3 m) = 0.7 m</em>

<em />

F₂₃ = -0.248 N

<h3>Net force between the charges</h3>

F(net) = F₁₃ + F₂₃

F(net) = 12.15 - 0.248

F(net) = 11.9 N

Thus, the total electric force that these charges exert on a third point charge is 11.9 N and the direction is towards positive y axis.

Learn more about electric force here: brainly.com/question/17692887

#SPJ1

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Answer:

α = 3×10^-5 K^-1

Explanation:

let ΔL be the change in length of the bar of metal, ΔT be the change in temperature, L be the original length of the metal bar and let α be the coefficient of linear expansion.

then, the coefficient of linear expansion is given by:

α = ΔL/(ΔT×L)

   = (0.3×10^-3)/(100)(100×10^-3)

   = 3×10^-5 K^-1

Therefore, the coefficient of linear expansion is 3×10^-5 K^-1

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3 years ago
A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0 m high cliff. At the instant the ball i
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Answer:

The distance traveled by the woman is 34.1m

Explanation:

Given

The initial height of the cliff

yo = 45m final, positition y = 0m bottom of the cliff

y = yo + ut -1/2gt²

u = 20.0m/s initial speed

g = 9.80m/s²

0 = 45.0 + 20×t –1/2×9.8×t²

0 = 45 +20t –4.9t²

Solving quadratically or by using a calculator,

t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s

So this is the total time it takes for the ball to reach the ground from the height it was thrown.

The distance traveled by the woman is

s = vt

Given the speed of the woman v = 6.00m/s

Therefore

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In a tug-of-war game on one campus, 15 students pull on a rope at both ends in an effort to displace the central knot to one sid
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Answer:

Net pull = 110 N to the left

Explanation:

Group the different pulls according to the direction (right or left)

2 pull 196 N each to the right

4 pull 98 N each to the left

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3 pull 150 N each to the right

1 pull 250 N to the left

Since positive direction is to the right, the pulls to the left will have a minus (-)

Net Force= 2(196)+4(-98)+5(-62)+3(150)+1(-250) \\Net Force = -110

The resulting force is negative, meaning the direction is to the left

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An open-topped freight car with mass 24,000 kg is coasting without friction along a level track. It is raining very hard, and th
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Answer:

(a) v = 3..6 m/s

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from the question we have the following:

mass of the car (Mc) = 24,000 kg

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final velocity of the car (v) = ?

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The most characteristic and real example is that of a pendulum at one end, as can be seen in the attached image.

When the pendulum is located at the top end, as shown in Figure 1, at that point the maximum potential energy will be held. Then the pendulum is released and when it passes through the reference point and its height is zero, with respect to that point, all potential energy will have become kinetic energy in the same way at this point the maximum speed of the pendulum will be set.

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