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Anettt [7]
4 years ago
12

A target at a shooting range is 60 yards away and 12 feet high. At what angle must the rifle be set to hit the target? Round to

the nearest hundredth.

Mathematics
1 answer:
Sunny_sXe [5.5K]4 years ago
5 0

Answer:

The angle must be at 3.81°

Step-by-step explanation:

The horizontal distance of the shooting range is 60 yards

The height of the target is 12ft.

We'll have to convert the value of the height from ft to yards.

1 yards = 3 foot

X yards = 12ft

X = 4yards.

The height of the target is 4 yards.

Now, to find the angle at which the shooter makes with the zenith of the target(height), we'll have to use use SOHCAHTOA

To know which of the rules we'll follow, a pictorial illustration of the values will help

(See attached document for better illustration).

From the diagram, we can see we have values at both opposite and adjacent.

Opposite = 4

Adjacent = 60

Hence we can use Tanθ = opposite/ adjacent

Tanθ = 4 / 60

Tanθ = 0.067

θ = Tan⁻0.067

θ = 3.81°

The angle at which the rifle must be set to hit the target is 3.81°

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What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
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What is the equation of the line passing through the points (–25, 50) and (25, 50) in slope-intercept form?
allochka39001 [22]

The equation of the line passing through the points (-25, 50) and (25, 50) in slope-intercept form is <u>y = 50</u>. Hence, <u>4th option</u> is the right choice.

The slope-intercept form of a line is written as y = mx + b, where m is the slope of the line, and b is the y-intercept.

The slope of a line passing through the points (x₁, y₁) and (x₂, y₂) can be calculated using the formula, slope (m) = (y₂ - y₁)/(x₂ - x₁).

Therefore, slope of the line passing through the points (-25, 50) and (25, 50) can be calculated as m = (50 - 50)/(25 - (-25)) = 0/(-50) = 0.

We can find the equation of the line using the point-slope formula, according to which, a line having a slope m and passing through the point (x₁, y₁) can be written as y - y₁ = m(x - x₁).

Therefore, the equation of the given line can be written as:

y - 50 = 0(x - 25)

or, y - 50 = 0,

or, y = 50.

Therefore, the equation of the line passing through the points (-25, 50) and (25, 50) in slope-intercept form is <u>y = 50</u>. Hence, <u>4th option</u> is the right choice.

Learn more about the equation of a line at

brainly.com/question/18831322

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9514 1404 393

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  A. 3×3

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  C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.

Step-by-step explanation:

A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.

This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...

  A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)

Matrix A is 3×3.

__

B. The second row of A represents the second equation:

  0x_1+1x_2+5x_3=-1

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.

__

C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)

6 0
3 years ago
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