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Anettt [7]
3 years ago
12

A target at a shooting range is 60 yards away and 12 feet high. At what angle must the rifle be set to hit the target? Round to

the nearest hundredth.

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0

Answer:

The angle must be at 3.81°

Step-by-step explanation:

The horizontal distance of the shooting range is 60 yards

The height of the target is 12ft.

We'll have to convert the value of the height from ft to yards.

1 yards = 3 foot

X yards = 12ft

X = 4yards.

The height of the target is 4 yards.

Now, to find the angle at which the shooter makes with the zenith of the target(height), we'll have to use use SOHCAHTOA

To know which of the rules we'll follow, a pictorial illustration of the values will help

(See attached document for better illustration).

From the diagram, we can see we have values at both opposite and adjacent.

Opposite = 4

Adjacent = 60

Hence we can use Tanθ = opposite/ adjacent

Tanθ = 4 / 60

Tanθ = 0.067

θ = Tan⁻0.067

θ = 3.81°

The angle at which the rifle must be set to hit the target is 3.81°

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~Ghostgate
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3 years ago
A student saves $3 dollars on August 1, $5 on August 2, $7 on August 3, and so on. How much will she save in August 20 ?
Delvig [45]
Here is your answer

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$3, &5, $7....

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a1= 3

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The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

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Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

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= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

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