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Tpy6a [65]
3 years ago
6

How are individual atoms of oxygen formed in the stratosphere?

Chemistry
2 answers:
zimovet [89]3 years ago
6 0
Individuals of oxygen are formed in the stratosphere when oxygen molecules that consist of two oxygen atoms are striked by ultraviolet light. This causes the atoms to split. 
ziro4ka [17]3 years ago
5 0

Answer:

d.

Individual oxygen atoms are formed when UV rays strike oxygen molecules.

Explanation:

When a UV ray strike oxygen molecules it seperates one oxygen molecule

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In a chemical reaction, atoms are rearranged to form new substances. This point
olga_2 [115]

Answer:

yes that is right

Explanation:

can i have a brainlist pwease

4 0
3 years ago
Carbon dioxide (CO2) fills a closed, rigid tank fitted with a paddle wheel, initially at 80°F, 30 lbf/in2, and a volume of 1.6 f
solong [7]

Answer:

The answer to this question can be given as:  

The initial pressure P= 30 lbf/in2

The initial temperature T1=80°F.

The initial volume=final volume V= 1.6 ft3.

Final  temperature T2=500°F

Heat transfer Q=-2.6 Btu.

pressure (P) (lbf/in2) change into lbf/ft2

P=30 lbf/in2=4320lbf/ft2.

Temperature (T1) °F change into °K

temperature T1=80°F=539.67 °K

Ideal gas formula:

M=PV/RT1.                   where T1=initial temperature.

M=4320*1.6/35.114*539.67.

M=0.364749 lb             Mass at Carbon dioxide (CO2).

DQ=DU+W            second law.

-2.6=MCV(T2-T1)+ W        

-2.6-(0.364749*1.6(500-80))=W

W=-27.111 b+u  am----> work done.

Explanation:

The explanation to this question can be given as:

Firstly we write the equation that is given in the question like, pressure, volume, gas constant, temperature. Then we covert the pressure and temperature into there possible values. Then We apply the formula of Ideal gas that is  M=PV/RT1. where M is  the mass, P is the pressure , V is the volume , R is the gas constant (0.08206 L·atm·K−1·mol−1)  and T1 is the initial temperature. Then we use the second formula that is DQ=DU+W. Where DQ= Heat transfer, DU=MCV(T2-T1)and W= work. It is used for finding work.

8 0
3 years ago
If you wanted to measure in irregular object's volume, which device would you use?
EleoNora [17]

Answer:

a beaker

Explanation:

3 0
3 years ago
Help pleas I dont understand
Temka [501]
The *independent* variable is the one that you always can control. However, the dependent variables are not since they **depend** on another.
4 0
3 years ago
Read 2 more answers
What is the theoretical yield of aspirin ( C 9 H 8 O 4 ), which has a molar mass of 180.15 g/mol, possible when reacting 3.03 g
pantera1 [17]

Answer:

The theoretical yield of aspirin is 3.95 grams

Explanation:

Step 1: Data given

Mass of salicylic acid = 3.03 grams

Volume of acetic anhydride = 3.61 mL

Density of acetic anhydride = 1.08 g/cm³

Step 2: The balanced equation

C4H6O3+C7H6O3→C9H8O4+C2H4O2

Step 3: Calculate moles salicylic acid

Moles salicylic acid = mass salicylic acid / molar mass salicylic acid

Moles salicylic acid = 3.03 grams /138.121 g/mol

Moles salicylic acid = 0.0219 moles

Step 4: Calculate mass acetic anhydride

Mass acetic anhydride = volume * density

Mass acetic anhydride = 3.61 mL * 1.08 g/mL

Mass acetic anhydride = 3.90 grams

Step 5: Calculate moles acetic anhydride

Moles acetic anhydride = 3.90 grams / 102.09 g/mol

Moles acetic anhydride = 0.0382 moles

Step 6: Calculate limiting reactant

For 1 mol salicylic acid we need 1 mol acetic anhydride to produce 1 mol aspirin

Salicylic acid is the limiting reactant. It will completely be consumed. (0.0219 moles). Acetic anhydride is in excess. There will react 0.0219 moles. There remain 0.0382 - 0.0219 =0.0163 moles

Step 7: Calculate moles aspirin

For 1 mol salicylic acid we need 1 mol acetic anhydride to produce 1 mol aspirin

For 0.0219 moles salicylic acid we'll have 0.0219 moles aspirin

Step 8: Calculate theoretical yield of aspirin

Mass of aspirin = moles aspirin *molar mass aspirin

Mass of aspirin = 0.0219 moles *180.15 g/mol

Mass of aspirin = 3.95 grams

The theoretical yield of aspirin is 3.95 grams

7 0
3 years ago
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