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jekas [21]
4 years ago
6

You need 150g of flour for 12 cakes how much flour do you need

Mathematics
2 answers:
Vaselesa [24]4 years ago
8 0

Answer:

12.5g for 1 cake, 150g for 12 cakes

Step-by-step explanation:

Because you need 150g for 12 cakes so 1 cake will take:

150 / 12 = 12.5g

So, You need 12.5g for 1 cake

Hope this help :3

mylen [45]4 years ago
5 0

<em>Answer and Step-by-step explanation:</em>

<em>For this question the answer is : 375 g of that wonderful flour.</em>

<em>According to the question:</em>

<em>150 g flour is for 12 cakes .</em>

<em>So, to find the missing value x g flour is for 30 cakes </em>

<em>Now we form in the equation: </em>

<em>x = (150 x 30) : 12 = 375 g of flour </em>

<em> That's the final answer ! - 375g of four,</em>

<em></em>

<em>Here's another method: </em>

<em> according to the question:</em>

<em>150 flour is for 12 cakes </em>

<em>So to find the missing value for 30 cakes ,</em>

<em> </em>

<em>30 : 12 = 2.5 </em>

<em>150 x 2.5 = </em><em>375 g flour </em>

<em></em>

<em>and that's the final answer : 375g of the wonderful flour.</em>

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Answer: 5.875 miles run on Friday to reach her goal by Jen

Step-by-step explanation:

Since we have given that

Part of distance covered on Monday by Jen is given by

4\frac{3}{4}=\frac{19}{4}

Part of distance covered on Tuesday by Jen is given by

5\frac{1}{8}\\\\=\frac{41}{8}

Part of distance covered on Wednesday by Jen is given by

0

Part of distance covered on Thursday by Jen is given by

6\frac{1}{4}\\\\=\frac{25}{4}

Total part of distance covered in these four days by Jen is given by

\frac{19}{4}+\frac{41}{8}+0+\frac{25}{4}\\\\=\frac{38+41+0+50}{8}\\\\=\frac{129}{8}=16.125\ miles

Remaining part of distance will be covered on Friday to reach her goal which is given by

22-16.125=5.875\ miles

Hence, 5.875 miles run on Friday to reach her goal by Jen.


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3 years ago
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3 years ago
Why would understanding perpendicular and parallel lines be extremely important to someone in construction? Provide an example o
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3 years ago
Which expression is equivalent to x y Superscript two-ninths?
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Option D: x\sqrt[9]{y^2} is the expression equivalent to xy^{\frac{2}{9}}

Explanation:

Option A: \sqrt{xy^9}

The expression can be written as ({xy^9})^{\frac{1}{2}

Applying exponent rule, we get,

x^{\frac{1}{2}} y^{\frac{9}{2}}

Thus, the expression \sqrt{xy^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option A is not the correct answer.

Option B: \sqrt[9]{xy^2}

The expression can be written as ({xy^2})^{\frac{1}{9}

Applying exponent rule, we get,

x^{\frac{1}{9}} y^{\frac{2}{9}}

Thus, the expression \sqrt[9]{xy^2} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option B is not the correct answer.

Option C: x\sqrt{y^9}

The expression can be written as x(y^9)^{\frac{1}{2} }

Applying exponent rule, we get,

x y^{\frac{9}{2}}

Thus, the expression x\sqrt{y^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option C is not the correct answer.

Option D: x\sqrt[9]{y^{2} }

The expression can be written as x(y^2)^{\frac{1}{9} }

Applying exponent rule, we get,

xy^{\frac{2}{9}}

Thus, the expression xy^{\frac{2}{9}} is equivalent to the expression xy^{\frac{2}{9}}

Hence, Option D is the correct answer.

4 0
3 years ago
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