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kompoz [17]
3 years ago
14

the produce department of a grocery store sold 288 pounds of tomatoes. the weight represented 72% of the shipment the store rece

ived. the rest spoiled and had to be discarded. how many pounds of tomatoes were originally received?
Mathematics
1 answer:
Shtirlitz [24]3 years ago
3 0
207.4 pounds originally was received

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6.
Degger [83]
Answer: True

---------------------------------

Work Shown:

Follow PEMDAS in reverse to solve for q
22q - 7 < 37
22q - 7+7 < 37+7 ... add 7 to both sides
22q < 44
22q/22 < 44/22 ... divide both sides by 22
q < 2
7 0
3 years ago
Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=
Ganezh [65]

Answer:

y(1+x)+x-5\ln xy=C

Step-by-step explanation:

Consider the given differential equation is

(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1

(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y

(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx

Taking all variables on right sides.

(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0

(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0

Let as assume,

M=-\frac{5}{x}+1+y and N=1-\frac{5}{y}+x

Find partial derivatives \frac{\partial M}{\partial y} and \frac{\partial N}{\partial x}

\frac{\partial M}{\partial y}=1 and \frac{\partial N}{\partial x}=1

Since \frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}, therefore the given differential equation is exact.

The solution of the exact differential equation is

\int Mdx+\int N(\text{without x)}dy=C

\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C

yx-5\ln x+x+y-5\ln y=C

y+x+xy-5\ln x-5\ln y=C

y(1+x)+x-5(\ln x+\ln y)=C

y(1+x)+x-5\ln xy=C

7 0
3 years ago
Evaluate Ic2 + b2l, given a = 5, b = -3, and c= -2.
LenKa [72]

Answer:

Ic² + b²l = 13 units.

Step-by-step explanation:

We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

Now, Ic² + b²l

= I(- 2)² + (- 3)²l {Putting the values of b and c}

= I4 + 9l  

= I13l

= 13 units.

Therefore, Ic² + b²l = 13 units. (Answer)

5 0
3 years ago
2 ACTIVITY: Estimating a Percents
Semenov [28]

Answer:

75 is 150% of 50!

3 0
1 year ago
Read 2 more answers
What’s the difference quotient simplified
mihalych1998 [28]

\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}

7 0
3 years ago
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