We are given with the mass of Arsine (
The mass of arsine is 15g
there is a relation between moles, mass and molar mass of any compound which is

The molar mass of Arsine = atomic mass of As + 3X atomic mass of H
the molar mass of Arsine = 74.92 + 3X 1 = 77.92 g/mol
Let us calculate the moles as

Answer:
The dog should be given half of 100 mg tablet in the morning and another half of 100 mg tablet in an evening.
Explanation:
Weight of the dog = 50 pounds = 22.68 kg
1 kg = 2.205 pounds
Amount of daily dose prescribed by doctor = 4.4 mg/kg
Total mount of dose = 4.4 mg/kg × 22.68 kg = 99.79 mg
99.79 mg ≈ 100 mg
49.89 mg ≈ 50 mg
So, according to doctor prescription dog should be given half 100 mg tablet in the morning and another half of 100 mg tablet in an evening.
In chemistry, yes...yes it is.
I hope this helps
Let me know if you have any questions
Haha ironically I had this problem not too long ago, I hope by this we will both be better students. Everyone just needs practice. Ok stop to pep talk and lets go. I'll try to go step by step.
<span>So basically since this is a balanced equation, the ratios of mols of the elements are equal, atom wise. </span>
<span>So you notice they give you Br2 is 1.0 kg (1000g) and that means there are 2 mols of Br2. And its asking for Cl2, (on the left) it also has 2 mols. </span>
<span>Then you can start from 1000g Br2 and multiply with 2 mol Br2 and 159.8g Br2 on the bottom. The 159 8 is the actual grams per mol. Then when you write this down, continue multipying with the next fraction. </span>
<span>Since you know the molar mass of Cl2 is 70.4 and you know theres 2 mols, you can say that 2 mols of Br2 = 2 mols of Cl2 so you should be able to multiple 2 mol Br2 / 159.8g Br2 with 70.4 g Cl2 / 2 mol Cl2. Bam the mols cancel out and you have the grams for Cl2. Multiple all that out and you should get 443g Cl2. Notice how the beginning question gives 2 significant figures, so technically 440g Cl2 is more of an exact number.</span>