In 5.70 mol of Hafnium there are 34,326
Potassium 23.5g/39.0983g/mol = 0.601mol
The Ratio of reactants is 2 to 1 so (0.601mol)/2 = 0.3005mol
Therefore 0.3005mol of F2 is needed to find liters use
formula V = nRT/P (V)Volume = 22.41L
(T)Temperature = 273K or 0.0 Celsius
(P)Pressure = 1.0atm
<span>(R)value is always .08206 with atm n = 0.3005moles
(273)(.08206)(0.3005)/1 = V V = 6.7319 Liters</span>
Answer:
Rubidium Sulfide
Explanation:
The chemical name for Rb2S is Rubidium Sulfide
Answer:
the answer is fe20 Hope this helps!
Explanation:
Answer:
The right response is "6 A". A further explanation is given below.
Explanation:
The given values are:
Resistance,
R = 6 ohms
Voltage,
V = 36 volts
As we know,
⇒ 
then,
⇒ 
On substituting the values, we get
⇒ 
⇒ 