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Readme [11.4K]
3 years ago
10

The veterinarian prescribes the NSAID carprofen for a 50-pound dog with arthritis at a dose of 4.4 mg/kg and would like this dos

e divided into two equal daily doses. In your hospital, you stock 25mg, 75mg, and 100 mg chewable tablets. What will you dispense and what are the directions?
Chemistry
1 answer:
alina1380 [7]3 years ago
8 0

Answer:

The dog should be given half of 100 mg tablet in the morning and another half of 100 mg tablet in an evening.

Explanation:

Weight of the dog = 50 pounds = 22.68 kg

1 kg = 2.205 pounds

Amount of daily dose prescribed by doctor = 4.4 mg/kg

Total mount of dose = 4.4 mg/kg × 22.68 kg = 99.79 mg

99.79 mg ≈ 100 mg

49.89 mg ≈ 50 mg

So, according to doctor prescription dog should be given half 100 mg tablet in the morning and another half of 100 mg tablet in an evening.

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How to do q solution, qrxn, moles of Mg , and delta Hrxn?
Helga [31]

Answer:

<em> 14, 508J/K</em>

ΔHrxn =q/n

where q = heat absorbed and n = moles

Explanation:

<em>m = mass of substance (g) = 0.1184g</em>

1 mole of Mg - 24g

<em>n</em> moles - 0.1184g

<em>n = 0.0049 moles.</em>

Also, q = m × c × ΔT

<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>

<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>

<em>= 14, 508 J/K/kg</em>

ΔT=  (final - initial) temp = 38.3 - 27.2

= 11.1 °C.

mass of MgCl2 = 95.211 × 0.1184 = 11.27

⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>

<em>= 1,7117.7472 J °C-1 g-1</em>

<em />

<em>∴ ΔHrxn = q/n</em>

<em>=1,7117.7472  ÷ 0.1184 </em>

<em>= 14, 508J/K</em>

6 0
3 years ago
Bacteria are usually blank organism<br><br><br> Pls help
DaniilM [7]

Answer:

single-celled organisms

Explanation:

8 0
3 years ago
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What is required for electrons to move from the stable energy level to an excited state?
Gekata [30.6K]

answer

When an electron temporarily occupies an energy state greater than its ground state, it is in an excited state. An electron can become excited if it is given extra energy, such as if it absorbs a photon, or packet of light, or collides with a nearby atom or particle

3 0
3 years ago
La rapidez a la que cantan los grillos de árbol es de 2.0 ×102 veces por minuto a 27°C, pero es sólo de 39.6 veces por minuto a
Lorico [155]

Answer:

51096J/mol = Energía de activación para el proceso del canto

Explanation:

Podemos solucionar este problema usando una forma de la ecuación de Arrhenius:

Ln\frac{K_2}{K_1} = \frac{-Ea}{R}  (\frac{1}{T_2} - \frac{1}{T_1} )

Donde K representa la velocidad de reacción (En este caso, la velocidad a la que cantan los grillos), Ea es la energía de activación, R la constante de los gases (8.314J/molK) y T representa la temperatura absoluta de 1, el estado inicial y 2, el estado final.

Estado inicial: K1 = 2.0x10²; T1 = 27°C + 273.15 = 300.15K

Estado final: K2 = 39.6; t2 = 5°C + 273.15 = 278.15K

Reemplazando en la ecuación:

Ln\frac{39.6}{2.0x10^2} = \frac{-Ea}{8.314J/molK}  (\frac{1}{278.15K} - \frac{1}{300.15K} )\\\\-1.6195 = \frac{-Ea}{8.314J/molK}*2.6351x10{-4}K{-1}

<h3>51096J/mol = Energía de activación para el proceso del canto</h3>
5 0
3 years ago
Which best describes a neutralization
Alinara [238K]
I think the answer is B
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3 years ago
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