MAg*cAg*(T1-T)=ρalc*Valc*calc*(T-T2)
mAg=?(g)
cAg=0.24J/gC
T1=95
T=23.5
Valc=25.6ml
ρalc=0.7893g/ml
T2=19.27
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Add an alkaline compound to raise the pH to 7.2.
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<u>Answer:</u> The number of gold atoms per cubic centimeters in the given alloy is 
<u>Explanation:</u>
To calculate the number of gold atoms per cubic centimeters for te given silver-gold alloy, we use the equation:

where,
= number of gold atoms per cubic centimeters
= Avogadro's number = 
= Mass percent of gold in the alloy = 42 %
= Density of pure gold = 
= Density of pure silver = 
= molar mass of gold = 196.97 g/mol
Putting values in above equation, we get:

Hence, the number of gold atoms per cubic centimeters in the given alloy is 