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Virty [35]
3 years ago
13

Bromine (Br2) is produced by reacting sea water with chlorine (Cl2) by the following reaction. What mass of Cl2 (in kg) is neede

d to produce 1.0 kg of Br2?
Chemistry
1 answer:
maxonik [38]3 years ago
5 0
Haha ironically I had this problem not too long ago, I hope by this we will both be better students. Everyone just needs practice. Ok stop to pep talk and lets go. I'll try to go step by step. 

<span>So basically since this is a balanced equation, the ratios of mols of the elements are equal, atom wise. </span>

<span>So you notice they give you Br2 is 1.0 kg (1000g) and that means there are 2 mols of Br2. And its asking for Cl2, (on the left) it also has 2 mols. </span>
<span>Then you can start from 1000g Br2 and multiply with 2 mol Br2 and 159.8g Br2 on the bottom. The 159 8 is the actual grams per mol. Then when you write this down, continue multipying with the next fraction. </span>

<span>Since you know the molar mass of Cl2 is 70.4 and you know theres 2 mols, you can say that 2 mols of Br2 = 2 mols of Cl2 so you should be able to multiple 2 mol Br2 / 159.8g Br2 with 70.4 g Cl2 / 2 mol Cl2. Bam the mols cancel out and you have the grams for Cl2. Multiple all that out and you should get 443g Cl2. Notice how the beginning question gives 2 significant figures, so technically 440g Cl2 is more of an exact number.</span>
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Zielflug [23.3K]

Answer:

A single bond, but it's also a hydrogen bond.

Explanation:

A hydrogen bond forms when hydrogen bonds to the 3 most electronegative atoms: Oxygen, Nitrogen, or Fluorine.

It's a single bond because hydrogen only has two valence electrons. Therefore, the rest of the electrons are placed around the nitrogen atom.

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3 years ago
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Mama L [17]

The question is incorrect, the correct question is;

Which of the following ground-state electron configurations represents the atom that has the

lowest first-ionization energy?

a) 1s2

b) 1s22s2

c) 1s22s22p6

d) 1s22s22p63s23p1

e) 1s22s22p63s23p3

The correct ground state configuration that represents the atom that has the lowest first ionization energy is 1s² 2s² 2p⁶ 3s² 3p¹.

The first ionization energy is the energy required to remove an electron from the outermost shell of an atom.

Ionization energy decreases down the group as number of shells increases but increases across the period as nuclear charge increase.

As the number of shells increases, the degree of shielding or screening decreases it easier to remove the outermost electron.

The elements whose ground state electronic configurations were shown are;

Helium - 1s²  

Beryllium - 1s² 2s²  

Neon - 1s² 2s² sp⁶  

Aluminum - 1s² 2s² 2p⁶ 3s² 3p¹    

Phosphorus - 1s² 2s² 2p⁶ 3s² 3p³

Aluminium (1s² 2s² 2p⁶ 3s² 3p¹) is a metal so it has the lowest first ionization energy since metals are highly electropositive.

Learn more: brainly.com/question/17783060

6 0
3 years ago
Why does the periodic table have the shape it has
Orlov [11]

Answer: The arrangement of electrons in atoms is responsible for the shape of the periodic table.

Explanation: Electron configurations can be predicted by the position of an atom on the periodic table.

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3 years ago
The vapor pressure of liquid iodomethane, CH3I, is 40.0 mm Hg at 249 K.A sample of CH3I is placed in a closed, evacuated contain
lora16 [44]

Explanation:

It is given that vapor pressure of liquid iodomethane is 40.0 mm Hg. So, if we calculate the vapor pressure according to the given values and if its value will be greater than the the given vapor pressure of iodomethane then it means that some of the vapors has converted into liquid state.

As the given values are as follows.

      P_{1} = 72.0 mm Hg,       T_{1} = 404 K

      P_{2} = ? ,               T_{2} = 249 K

As volume is constant so, according to Gay-Lussac's law pressure is directly proportional to temperature.

                      P \propto T         (at constant volume)

or,                    \frac{P}{T} = k

Therefore, the formula to calculate the value of P_{2} is as follows.

              \frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}

            \frac{72.0 mm Hg}{404 K} = \frac{P_{2}}{249 K}

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As calculated vapor pressure is more than the given vapor pressure. Hence, the liquid will convert into gas.

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