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garik1379 [7]
3 years ago
11

Help !!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
horsena [70]3 years ago
3 0
I hope this helps
Let me know if you have any questions

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<span>389.88094 amu First we look up the atomic mass of all elements contained in calcium iodate using the periodic table: Ca: 40.078 I: 126.90447 O: 15.999 As an intermediate step we calculate the molecular mass of the ion IO3: 126.90447 + 3*15.999 = 174.90147 Then we calculate the mass of one calcium atom and 2 iodate ions: 2*174.90147 + 40.078 = 389.88094 amu</span>
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Hello,

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