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Marianna [84]
3 years ago
12

What is the compound name for NF

Chemistry
2 answers:
svetoff [14.1K]3 years ago
5 0

Answer:

Nathan Feuerstein

Explanation:

dlinn [17]3 years ago
4 0

Nitrogen trifluoride is the inorganic compound with the formula NF3. This nitrogen-fluorine compound is a colorless, odorless, nonflammable gas. It finds increasing use as an etchant in microelectronics.

(If you mean by a gas of some sort)

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A chef makes a marinade by mixing red pepper flakes, dried onion flakes, and a ground ginger with soy sauce. He sets the marinad
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Answer:

Suspension

Explanation:

This mixture is a simple suspension.

A suspension is a mixture of small insoluble particles of a solid in a liquid or gas. Here, it is insoluble particles in liquid.

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  • The particles do not pass through ordinary filter paper.
  • They are usually cloudy and have an opaque color.
  • The marinade is simply a suspension.
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Why do atoms of nonmetals form anions? Support your answer with an example.
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What property of gases confirms that the space between the particles of gas is significantly larger than when the same substance
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5 0
3 years ago
Mn2+
snow_lady [41]

The molarity of the stock Mn²⁺ ions is 0.0288 M

Based on the dilution formula;

  • The molarity of A is 0.00144 M
  • The molarity of B is 0.0000576 M
  • The molarity of C is 0.000001152 M

<h3>What is the molarity of a solution?</h3>

The molarity of a solution is the number of moles of a solute dissolved in a given volume of solution in liters.

  • Molarity = number of moles/volume

The molarity of the stock solution is:

moles of Mn²⁺ ions = mass / molar mass

molar mass of  Mn²⁺ ions = 55.0 g/mol

moles of Mn²⁺ ions = 1.584 / 55

moles of Mn²⁺ ions = 0.0288 moles

molarity of Mn²⁺ ions = 0.0288 / 1

molarity of Mn²⁺ ions = 0.0288 M

The dilution formula is used to determine the molarities of A, B, and C.

C₁V₁ = C₂V₂

C₂ = C₁V₁ / V₂

Where;

  • C₁ = initial molarity
  • V₁ = initial volume
  • C₂ = final molarity
  • V₂ = final volume

Molarity of A = 50 * 0.0288 / 1000

Molarity of A = 0.00144 M

Molarity of B = 10 * 0.00144 / 250

Molarity of B = 0.0000576 M

Molarity of C = 10 * 0.0000576 / 500

Molarity of C = 0.000001152 M

Learn more about molarity at: brainly.com/question/17138838

#SPJ1

5 0
1 year ago
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