Answer:
Jjzjxjzjjzzzkmzkzkzjzjzjxjj j jxkiIIJzizjcjxnJ zbuzbx zbah z
Each type of electromagnetic radiation and placed in order of increasing photon energy and increasing frequency
- FM Radio waves < Visible light < X - rays
- Order of increasing frequency.
- FM Radio waves < Visible light < X - rays
This is further explained below.
<h3>What is
electromagnetic radiation?</h3>
Parameters
Frequency =107 100 000 hertz
Wavelength, λ = c / ν => 2.8 m => 2.12 * 10-10 m
Energy = 3.97 * 10 -19 J/ photon.
Generally, the equation for Wavelength is mathematically given as
λ = h c / E
Therefore
λ =6.626 * 10-34 * 3 * 108 / (3.97* 10 -19 J)
λ =5 * 10-7 m
In conclusion, This is considered to be part of the viewable area (green Increasing photon energy from lowest to highest.
- FM Radio waves < Visible light < X - rays
- Order of increasing frequency.
- FM Radio waves < Visible light < X - rays
Read more about electromagnetic radiation
brainly.com/question/11895806
#SPJ1
2.2 x 10^-2
0.055 / 250 = 0.00022 - This would be 2.2 x 10^-4, but the question is asking for percent, not proportion, so multiply by 100% to get the percentage.
0.00022 * 100% = 0.022% = 2.2 * 10^-2
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask.
1mmol = 10^-3 mol
Therefore 4.10*10^-5mmol = 4.10*10^-8mol
molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol
You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below)
But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g
Mass is = 9.75*10^-7 grams
1µg = 10^-6 g
You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4
(*see below) at this point you could have said:
1µg = 10^-6 g therefore you have a solution of 6.29µg per litre,
155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>