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Svetllana [295]
3 years ago
10

When an electric field is applied to a metallic crystal, the movement of electrons is .

Chemistry
2 answers:
Talja [164]3 years ago
8 0
Your answer is random because metals form huge structures in which electrons in the outer shell of the metal it makes atoms free to move. 
Katyanochek1 [597]3 years ago
6 0
The answer would be Directional. The movement of electrons is directional.
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The relation between stability and solubility​
Tema [17]

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3 years ago
One type of electromagnetic radiation has a frequency of 107.1MHz,another type has wavelength of of 2.12x10^-10 m,and another ty
Andreas93 [3]

Each type of electromagnetic radiation and placed in order of increasing photon energy and increasing frequency

  • FM Radio waves < Visible light < X - rays
  • Order of increasing frequency.
  • FM Radio waves < Visible light < X - rays

This is further explained below.

<h3>What is electromagnetic radiation?</h3>

Parameters

Frequency =107 100 000 hertz

Wavelength, λ = c / ν => 2.8 m => 2.12 * 10-10 m

Energy = 3.97 * 10 -19 J/ photon.

Generally, the equation for Wavelength is  mathematically given as

λ = h c / E

Therefore

λ =6.626 * 10-34  * 3 * 108  / (3.97* 10 -19 J)

λ =5 * 10-7 m

In conclusion, This is considered to be part of the viewable area (green Increasing photon energy from lowest to highest.

  • FM Radio waves < Visible light < X - rays
  • Order of increasing frequency.
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Read more about electromagnetic radiation

brainly.com/question/11895806

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5 0
1 year ago
A single 250 gram
Gala2k [10]

2.2 x 10^-2

0.055 / 250 = 0.00022 - This would be 2.2 x 10^-4, but the question is asking for percent, not proportion, so multiply by 100% to get the percentage.

0.00022 * 100% = 0.022% = 2.2 * 10^-2

6 0
3 years ago
Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. be sure your answer has the correct number
Vera_Pavlovna [14]
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. 1mmol = 10^-3 mol Therefore 4.10*10^-5mmol = 4.10*10^-8mol molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below) But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g Mass is = 9.75*10^-7 grams 1µg = 10^-6 g You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4 (*see below) at this point you could have said: 1µg = 10^-6 g therefore you have a solution of 6.29µg per litre, 155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>
3 0
3 years ago
Using ethanol and sodium or potassium cyanide as the sources of the carbon atoms, along with any necessary inorganic reagents, s
11Alexandr11 [23.1K]

Answer:

Please see attachment

Explanation:

Please see attachment

3 0
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