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3 years ago

How many moles of SO2 will be produced from 11.5 moles of O2?

Chemistry

1 answer:

pshichka [43]3 years ago

8 0

Explanation:

Respuesta: La masa atómica del carbono (C) es 12 g/mol; para el oxígeno (O) es de 16 g/mol. Esto significa que 6.022 x 1023 átomos de carbono pesan 12 gramos. Según esto, el peso molecular del CO2 es: 12 g/mol [C] + 2 x 16 g/mol [O2] = 44 g/mol

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Do nonliving things have cells

OLEGan [10]

Nonliving thing doesn’t have cell

4 0

3 years ago

Read 2 more answers

A party balloon contains 5.50 x 10 ^22 atoms of helium gas. What is the mass, in grams of the

eduard

Answer:

$\boxed {\boxed {\sf A. \ 0.365 \ g\ He}}$

Explanation:

<u>1. Convert Atoms to Moles</u>

We must use Avogadro's Number: 6.022*10²³. This is the number of particles (atoms, molecules, ions, etc.) in 1 mole of a substance. In this case, the particles are atoms of helium. We can create a ratio.

$\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}$

Multiply by the given number of helium atoms.

$5.50 *10^{22} \ atoms \ He *\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}$

Flip the fraction so the atoms of helium cancel.

$5.50 *10^{22} \ atoms \ He *\frac {1 \ mol \ He}{6.022*10^{23} \ atoms \ He}$

$5.50 *10^{22} *\frac {1 \ mol \ He}{6.022*10^{23} }$

$\frac {5.50 *10^{22} \ mol \ He}{6.022*10^{23} }= 0.09133178346 \ mol \ He$

<u>2. Convert Moles to Grams</u>

We must use the molar mass, which is found on the Periodic Table.

Helium (He): 4.00 g/mol

Use this as a ratio.

$\frac { 4.00 \ g \ He }{ 1 \ mol \ He}$

Multiply by the number of moles we calculated. The moles will then cancel.

$0.09133178346 \ mol \ He *\frac { 4.00 \ g \ He }{ 1 \ mol \ He}$

$0.09133178346*\frac { 4.00 \ g \ He }{ 1 }$

$0.3653271338 \ g\ He$

<u>3. Round </u>

The original measurement has 3 significant figures (5, 5, and 0). Our answer must have the same. For the number we calculated, it is thousandth place. The 3 in the ten thousandth place tells us to leave the 5.

$0.365 \ g\ He$

The mass is <u>0.365 grams of helium</u> so choice A is correct.

7 0

2 years ago

A compound is 53. 31% c, 11. 18% h, and 35. 51% o by mass. What is its empirical formula? insert subscripts as needed.

lyudmila [28]

Answer:

C2H5O

Explanation:

In a 100 g sample we would have

53.31 g of C

11.18g of H

35.51g of O

First, we find the relative number of atoms of each element by dividing the number of grams the element has in the compound by its atomic mass.

Atomic mass of carbon is 12.011

Relative number of carbon atoms = 53.31 / 12.011 = 4.4

Atomic mass of hydrogen = 1.007

Relative number of hydrogen atoms : 11.18/1.007 = 11.1

Atomic mass of oxygen : 15.999

Relative number of oxygen atoms : 35.51 / 15.999 = 2.2

Now we find a ratio of the relative number of atoms by dividing the # of relative atoms of each element by the element's relative number of atoms that had the lowest number. ( oxygen which had 2.2 ) The outcome of each will be the subscript or number of atoms of each element.

Carbon : 4.4 / 2.2 = 2

Hydrogen : 11.1 / 2.2 = 5

Oxygen : 2.2 / 2.2 = 1

The answer is C2H5O

8 0

2 years ago

Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equ

DedPeter [7]

Answer:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

Explanation:

Solid Iron = Fe

Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).

Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)

Metal Copper = Cu

Writing the equation using symbols leaves us with:

Fe + CuNO₃ → Fe(NO₃)₃ + Cu

<em>It is not balanced yet</em>. Now we <u>balance the NO₃ species on the left side</u>:

Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu

Finally we<u> balance the Cu species on the right side</u>:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

5 0

2 years ago

Calculate the density of sulfuric acid from the information that 35.4 mL of the acid masses 65.14 g.

vladimir1956 [14]

Answer:

<h3>The answer is 1.84 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{65.14}{35.4} \\ = 1.840112994...$

We have the final answer as

Hope this helps you

3 0

2 years ago