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masya89 [10]
3 years ago
12

A polarized Light of intensity I0 is incident on an analyzer. What should the angle between the axis of polarization of the ligh

t and the transmission axis of the analyzer be to allow 38% of the total intensity to be transmitted?
Physics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer:

The the angle between the axis of polarization of the light and the transmission axis of the analyzer is 52⁰.

Explanation:

Given;

I₀  as incident light intensity

The intensity of a linearly polarized light passing through a polarizer is given by Malus' law:

I = I₀Cos²θ

where;

I is the intensity after passing through the analyzer

θ is the the angle between the axis of polarization of the light and the transmission axis of the analyzer.

If 38% of the total intensity is transmitted, then I = 38% of I₀ = 0.38I₀

0.38I₀ = I₀Cos²θ

0.38 = Cos²θ

Cosθ = √0.38

Cosθ = 0.6164

θ  = Cos⁻¹ (0.6164)

θ  = 51.95° = 52⁰

Therefore, the angle between the axis of polarization of the light and the transmission axis of the analyzer to allow 38% of the total intensity to be transmitted is 52⁰.

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