<span>1.02x10^2 ml
Since molarity is defined as moles per liter, the product of the molarity and volume will remain constant as mole solvent is added. So let's set up an equality to express this
m0*v0 = m1*v1
where
m0, v0 = molarity and volume of original solution
m1, m1 = molarity and volume of final solution.
Solve for v0, then substitute the known values and calculate:
m0*v0 = m1*v1
v0 = (1.75 M * 500 ml)/8.61 M
v0 = (1.75 M * 500 ml)/8.61 M
V0 = 101.6260163
Rounding to 3 significant figures gives 102 ml.
So the original volume of the 8.61 M H2SO4 solution was 102 ml or 1.02x10^2 ml.</span>
Answer:
A solution is a heterogeneous mixture
Explanation:
This statement that a solution is a heterogeneous mixture is completely and totally wrong.
A solution is a homogeneous mixture.
Homogeneous mixtures have their constituents existing in just one phase.
- It is a homogeneous mixture of solutes and solvents.
- In a solution, the solutes particles are distributed uniformly in the solvent.
- The solute is the substance that is dissolved to make the solution.
- Solutes are usually present in a small amount than the solvent.
- The solvent acts as the dispersing medium which allows the solute to go into the solution.
- The solute can be solid, liquid or gas.
Answer
Manual samplers are prone to effects of temperature, speed of wind and air concentrations.
Explanation
Manual samplers face several challenges that can act as drawbacks to obtaining accurate results. They are subjected to effects of sampling duration where long sampling times are needed to obtain adequate mass for detection. Manual samplers face challenges when measuring non-volatile species because particles are observed into the adsorption medium at a slower rate of diffusion.
Answer:
I think it is c
Explanation:
When water turns into water vapor it goes into the air so it must be lighter
Answer:
Four substitution products are obtained. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule
Explanation:
An SN1 reaction usually involves the formation of a carbocation in the slow rate determining step. This carbocation is now attacked by a nucleophile in a subsequent fast step to give the desired product.
However, the product is obtained as a racemic mixture because the nucleophile may attack from the top or bottom of the carbocation hence both attacks are equally probable.
The attacking nucleophile in this case may be water or CH3OH
