<h3>
Answer:</h3>
272.43 K or -0.718°C
<h3>
Explanation:</h3>
We are given;
The initial pressure,P1 as 761 mmHg
Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K
Final pressure as 759 mmHg
We are required to calculate the final temperature;
According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.
That is; Pα T
Therefore, at varying pressure and temperature,
![\frac{P1}{T1}=\frac{P2}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7BP1%7D%7BT1%7D%3D%5Cfrac%7BP2%7D%7BT2%7D)
To get final temperature;
![T2=\frac{P2T1}{P1}](https://tex.z-dn.net/?f=T2%3D%5Cfrac%7BP2T1%7D%7BP1%7D)
![T2=\frac{(759 mmHg)(273.15K)}{761 mmHg}](https://tex.z-dn.net/?f=T2%3D%5Cfrac%7B%28759%20mmHg%29%28273.15K%29%7D%7B761%20mmHg%7D)
![T2=272.43K](https://tex.z-dn.net/?f=T2%3D272.43K)
Therefore, the final temperature will be 272.43 K or -0.718°C