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Radda [10]
3 years ago
14

if a gas sample has a pressure of 761 mmhg at 0.00°c by how much does the temperature have to decrease to lower the pressure to

759 mmhg?​
Chemistry
1 answer:
Nady [450]3 years ago
6 0
<h3>Answer:</h3>

272.43 K or -0.718°C

<h3>Explanation:</h3>

We are given;

The initial pressure,P1 as 761 mmHg

Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K

Final pressure as 759 mmHg

We are required to calculate the final temperature;

According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.

That is; Pα T

Therefore, at varying pressure and temperature,

\frac{P1}{T1}=\frac{P2}{T2}

To get final temperature;

T2=\frac{P2T1}{P1}

T2=\frac{(759 mmHg)(273.15K)}{761 mmHg}

T2=272.43K

Therefore, the final temperature will be 272.43 K or -0.718°C

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The answer to your question is  1.83 x 10²⁵ particles

Explanation:

Data

particles of H₂O = ?

mass of H₂O = 546 g

Process

1.- Calculate the molar mass of Water

Molar mass = (2 x 1) + (1 x 16)

                   = 2 + 16

                   = 18 g

2.- Use proportions to find the number of particles. Use Avogadro's number.

                 18 g ---------------- 6.023 x 10²³ particles

                546 g ---------------   x

                  x = (546 x 6.023 x 10²³) / 18

3.- Simplification

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4.- Result

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