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Radda [10]
3 years ago
14

if a gas sample has a pressure of 761 mmhg at 0.00°c by how much does the temperature have to decrease to lower the pressure to

759 mmhg?​
Chemistry
1 answer:
Nady [450]3 years ago
6 0
<h3>Answer:</h3>

272.43 K or -0.718°C

<h3>Explanation:</h3>

We are given;

The initial pressure,P1 as 761 mmHg

Initial temperature, T1 as 0.00°C which is equivalent to 273.15 K

Final pressure as 759 mmHg

We are required to calculate the final temperature;

According to pressure law, the pressure of a gas and absolute temperature are directly proportional at constant volume.

That is; Pα T

Therefore, at varying pressure and temperature,

\frac{P1}{T1}=\frac{P2}{T2}

To get final temperature;

T2=\frac{P2T1}{P1}

T2=\frac{(759 mmHg)(273.15K)}{761 mmHg}

T2=272.43K

Therefore, the final temperature will be 272.43 K or -0.718°C

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Is O2 always a double bond?
Dima020 [189]
  • O-O single bonds and H-O single bonds in \text{H}_2\text{O}_2 molecules.
  • H-O single bonds in \text{H}_2\text{O} molecules.
  • O=O double bonds in \text{O}_2 molecules.
<h3>Explanation</h3>

How many valence electrons do atoms in each molecule need for them to be stable?

  • Each H atom needs two valence electrons to be stable.
  • Each atom of an element other than H needs eight valence electron to be stable.
  • There are two H atoms and two O atoms in an  \text{H}_2\text{O}_2 molecule. Atoms in each \text{H}_2\text{O}_2 need 2 \times 1 + 2\times 2 = 6 more electrons to be stable.
  • There are two H atoms and one O atom in an \text{H}_2\text{O} molecule. Atoms in each \text{H}_2\text{O} molecule need 2 \times 1 + 2= 4 more electrons to be stable.
  • There are two O atoms in an \text{O}_2 molecule. Atoms in each \text{O}_2 molecule need 2 \times 2 = 4 more electrons to be stable.

How many chemical bonds in each molecule?

Each chemical bond adds one valence electron to each bonding atom. Each chemical bond connects two atoms. As a result, each chemical bond adds two valence electrons to the molecule.

  • Each \text{H}_2\text{O}_2 molecule needs 6 / 2 = 3 chemical bonds.
  • Each \text{H}_2\text{O} molecule needs 4 / 2 = 2 chemical bonds.
  • Each \text{O}_2 molecule needs 4 /2= 2 chemical bonds.

What chemical bonds are these? Again, each H atom needs only one more valence electron to be stable. It will share only one electron with O and form one H-O bond. The rest of the chemical bonds are between O atoms.

  • There are two H atoms in each \text{H}_2\text{O}_2 molecule, which form two H-O bonds. Two of the three chemical bonds in this molecule are H-O. The other is an O-O single bond between the two O atoms.
  • There are two H atoms in each \text{H}_2\text{O} molecule, which form two H-O bonds. Both chemical bonds in this molecule are H-O. There's no O-O bond in this molecule.
  • There is no H atom in \text{O}_2 molecules. Both chemical bonds are between O atoms. However, there are only two O atoms. There must be two chemical bonds between the two O atoms. That bond will be an O-O double bond.
3 0
3 years ago
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At archery practice, Vladimir tests a bow and arrow he has recently designed. He is able to accelerate a 24.0-g arrow at an aver
Whitepunk [10]

Answer: A

1.68 N

Explanation:

F = ma = 0.024(70.0) = 1.68 N

7 0
3 years ago
Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be su
Free_Kalibri [48]

Answer:

Volume = 746 L

Explanation:

Given that:- Mass of copper(II) fluoride = 175 g

Molar mass of copper(II) fluoride = 101.543 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{175\ g}{101.543\ g/mol}

Moles_{copper(II)\ fluoride}= 1.7234\ mol

Also,

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

So,,

Volume =\frac{Moles\ of\ solute}{Molarity}

Given, Molarity = 0.00231 M

So,

Volume =\frac{1.7234}{0.00231}\ L

<u>Volume = 746 L</u>

7 0
3 years ago
Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
barxatty [35]

Answer: 353.6 g.


Explanation:


1) Word equation (given)

Sodium phosphate + calcium choride → sodium chloride + calcium phosphate


2) Balanced chemical equation

2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂


3) Mole ratio

2 moles Na₃PO₄ : 3 moles CaCl₂ :  6 moles NaCl : 1 mole Ca₃(PO4)₂


4)  Formula to convert grams to moles

number of moles = mass in grams / molar mass


5) Number of moles of limiting reactant

a) mass in grams = 379.4 g CaCl₂

b) molar mass CaCl₂ = 110.98 g/mol

c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles


6) Theoretical yield of Ca₃(PO4)₂

    3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒

    x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂


7) Convert 1.140 moles Ca₃(PO4)₂

a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol

b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.

7 0
4 years ago
PLEASE HELP ME !!!!!!
Leviafan [203]

Answer: b

Explanation:

By adding heat you are adding more energy

5 0
4 years ago
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