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MrMuchimi
2 years ago
5

Corrosion may be regarded as the destruction of metal by:

Chemistry
1 answer:
NeX [460]2 years ago
4 0
All of the above I think it might not be right
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What mass of sodium sulfate is needed to make 2.5 L of 2.0 M solution?
Serjik [45]
D) 710 g

Step by Step:
Multiply 2.5 L by 2.0 M to solve for moles
2 mol/L • 2.5 L= 5 mol

Find formula weight of sodium sulfate

Na2SO4-142.04 g/mol

Na- 2(22.99)=45.98
S-32.06
O-4(16)=64

Multiply miles by formula weight

5 mole • 142.04 g/mol=710.2 g
7 0
2 years ago
At 400 K oxalic acid decomposes according to the reaction:H2C2O4(g)→CO2(g)+HCOOH(g)In three separate experiments, the intial pre
padilas [110]

Answer:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

Explanation:

For the reaction:

H₂C₂O₄(g) → CO₂(g) + HCOOH(g)

At t = 0, the initial pressure is just of H₂C₂O₄(g). At t= 20000 s, pressures will be:

H₂C₂O₄(g) = P₀ - x

CO₂(g) = x

HCOOH(g) = x

P at t=20000 is:

P₀ - x + x + x = P₀+x. That means P at t=20000s - P₀ = x

For 1st point:

x = 92,8-65,8 = 27

Pressure of H₂C₂O₄(g) at t=20000s: 65,8-27 = 38,8

2nd point:

x = 130-92,1 = 37,9

H₂C₂O₄(g): 92,1 - 37,9 = 54,2

3rd point:

x = 157-111 = 46

H₂C₂O₄(g): 111-46 = 65

Now, as the rate law is :

v = k P[H₂C₂O₄]

Based on integrated rate law, k is:

(- ln P[H₂C₂O₄] + ln P[H₂C₂O₄]₀) / t = k

1st point:

k = 2,64x10⁻⁵

2nd point:

k = 2,65x10⁻⁵

3rd point:

k = 2,68x10⁻⁵

The averrage of this values is:

k = 2,66x10⁻⁵

That means law is:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

I hope it helps!

4 0
2 years ago
What is the percent composition of hydrogen (H) in benzene (C6H6)?
PtichkaEL [24]
That's the answer on that picture

6 0
2 years ago
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Describe the development of the modern periodic table
Simora [160]
There had been new discoveries of chemicals that have been added to the periodic table in recent years
8 0
2 years ago
True or False: The only planet that has gravity is the Earth.
taurus [48]

Answer:

False.

Explanation:

all planets have gravity because if they didnt, the gasses and whatever makes up the planet wouldnt be pulled down to the core of the planet, and it would just be floating around in space.

6 0
3 years ago
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