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2 years ago

5

Corrosion may be regarded as the destruction of metal by:

1 answer:

NeX [460]2 years ago

4 0

All of the above I think it might not be right

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miss Akunina [59]

Answer:

$\boxed{\text{40 mol Al}}$

Explanation:

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n/mol: 20

$\text{Moles of Al} = \text{20 mol Al$_{2}$O$_{3}$}\times \dfrac{\text{2 mol Al}}{\text{1 mol Al$_{2}$O$_{3}$}}= \textbf{40 mol Al}\\\text{You can produce }\boxed{\textbf{40 mol Al}}$

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