The Chemical fomulla for Zinc Phosphate
Zn3(PO4)2
The half-life of polonium-210, given that it decays from 98.3 micrograms to 12.3 micrograms in 414 days is 138 days
<h3>How to determine the number of half-lives </h3>
- Original amount (N₀) = 98.3 micrograms
- Amount remaining (N) = 12.3 micrograms
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 98.3 / 12.3
2ⁿ = 8
2ⁿ = 2³
n = 3
<h3>How to determine the half life </h3>
- Number of half-lives (n) = 3
- Time (t) = 414 days
- Half-life (t½) = ?
t½ = t / n
t½ = 414 / 3
t½ = 138 days
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Answer:
Explanation:
Data:
p₁ = 1.00 atm; V₁ = 350. L
p₂ = ?; V₂ = 2.00 L
Calculation:
The second one, the third one, and the fourth one
