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Whitepunk [10]
2 years ago
14

The difference between the calculated voltage (based on standard potentials) and the actual voltage required to cause electrolys

is is called .
Chemistry
1 answer:
Mrrafil [7]2 years ago
5 0

The difference between the calculated voltage (based on standard potentials) and the actual voltage required to cause electrolysis is called overvoltage.

<h3>Electrolysis </h3>

Electrolysis is the technique of causing a chemical change in a substance by passing an electric current through it. The substance either loses or gets an electron during the chemical transition (oxidation or reduction). The procedure is carried out in an electrolytic cell, a device made up of positive and negative electrodes that are kept apart and submerged in a solution with ions that are both positively and negatively charged. The chemical that needs to be converted might either be dissolved in the solution or could form the electrode. The negatively charged electrode (cathode) receives electrical current (i.e., electrons), which travels there and combines with the components of the solution to convert them (reduced).

Learn more about electrolysis here:

brainly.com/question/12054569

#SPJ4

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Oxygen in the air combines with the copper statue to form copper oxide, which is green. Which of these is the correct chemical r
ss7ja [257]

D, 2Cu + O2 → 2CuO. A is wrong because oxygen is a diatomic element, meaning it always has to come in the form of O2 in the case of gas. B is wrong because the equation isn't balanced correctly; there's two oxygens on the reactants side, while only one oxygen on the products side. C is wrong because it's saying you're STARTING OUT with CuO already: that doesn't correspond with the word problem. Thus leaves D, where the equation is balanced correctly, has the diatomic oxygen, and ends with CuO.

7 0
3 years ago
Describe the three main types of plate boundary interactions:
bulgar [2K]

Answer:

In the explanation

Explanation:

Divergent: When two plates are diverging from each other, meaning that the two plates are moving away from each other. Events that may occur include ridges or rifts.

Convergent: When two plates are moving towards each other.

If a continental plate and an oceanic plate are converging, the oceanic plate would slide underneath the continental plate since it is thinner. This would result in subduction, which means that part of the oceanic plate would hang underneath the continental plate, where magma can melt the hanging part.

If two continental plates are converging, the crash would result in mountains or volcanic activity. Magma could rise and rush from the crack. There would be a bump in these tectonic plates.

Transform: When two plates are sliding past each other. Earthquakes can occur when the plates are sliding. When an oceanic plate is involved, the movement of the plates could cause a tsunami as well. The water above the transform fault could rise, and grow bigger and bigger. The 2011 Japan Tsunami is a good example of this.

Hope this helps!

5 0
3 years ago
A 100.0 ml sample of 0.18 m hclo4 is titrated with 0.27 m lioh. determine the ph of the solution after the addition of 100.0 ml
Naddika [18.5K]
(I think you have a mistake in your question as the addition is 30mL, not 100mL)
when PH = - ㏒[H+]
and here we have HClO4 is the strong acid
So PH = - ㏒[HClO4]

moles of HClO4 = 0.1 L *0.18 m = 0.018 M
moles of LiOH = 0.03 L * 0.27 m = 0.0081 M
when the total volume = 0.1L + 0.03L =  0.13 L
∴ [HClO4] = (0.018-0.0081)/0.13 L
                 = 0.076 M
PH = -㏒ 0.076
      = 1.12
5 0
4 years ago
Read 2 more answers
4.
vova2212 [387]

Answer:

33.3gtts/min

Explanation:

We can find the drops/minute with common proportions.

100cc/1hr * 200gtts/1cc * 1hr/60min ≈ 33.3gtts/min

Best of Luck!

6 0
3 years ago
If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
gizmo_the_mogwai [7]
 The ore contains 55.4% calcium phosphate (related to the mineral apatite) so the amount of Ca3(PO4)2 is 55.4%x=1000g so x=1000/0.554= 1.805kg. Now for the % of P in this amount of calcium phosphate, use all the masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95  (NB oxygen is 16 mass x 4 =64) so the total mass is 310.2 and we have 61.95 of P (Pmass x 2) so 61.95/3102.= 0.19 or 19% P. So of the 1.805 x 0.19= 0.34kg of phosphorus.
8 0
4 years ago
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