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Whitepunk [10]
2 years ago
14

The difference between the calculated voltage (based on standard potentials) and the actual voltage required to cause electrolys

is is called .
Chemistry
1 answer:
Mrrafil [7]2 years ago
5 0

The difference between the calculated voltage (based on standard potentials) and the actual voltage required to cause electrolysis is called overvoltage.

<h3>Electrolysis </h3>

Electrolysis is the technique of causing a chemical change in a substance by passing an electric current through it. The substance either loses or gets an electron during the chemical transition (oxidation or reduction). The procedure is carried out in an electrolytic cell, a device made up of positive and negative electrodes that are kept apart and submerged in a solution with ions that are both positively and negatively charged. The chemical that needs to be converted might either be dissolved in the solution or could form the electrode. The negatively charged electrode (cathode) receives electrical current (i.e., electrons), which travels there and combines with the components of the solution to convert them (reduced).

Learn more about electrolysis here:

brainly.com/question/12054569

#SPJ4

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What are the differences between cholesterol and ergosterole?​
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The difference between ergosterol and cholesterol is much more obvious in their interactions with POPC and DOPC. Whereas cholesterol induces a strong condensing effect that thickens both POPC and DOPC bilayers, ergosterol shows no condensing effect in POPC and DOPC at all.
5 0
3 years ago
4 Physical characteristics of: a glass of milk, a candle, a piece of aluminum foil, a spoonful of sugar, and toothpaste
Nadya [2.5K]
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6 0
3 years ago
What is the classification of a solution of naoh with a ph of 8.3?
Maksim231197 [3]

Answer:

  • <u>Alkaline or basic solution </u>(alkaline and basic means the same)

Explanation:

According to the <em>pH</em>,  solutions may be classified as neutral, acidic, or alkaline (basic).

This table shows such classification:

pH               classification

  7                   neutral

> 7                   alkaline or basic

< 7                   acidic

Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).

Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.

  • pH = - log [H₃O⁺]

You can calculate the concentration of hydronium ions using antilogarithm properties:

pH=-log[H_3O^+]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-8.3}=0.00000000501

NaOH solutions are alkaline solutions, bases, according to Arrhenius model,  because they contain OH⁻ ions and release them when ionize in water.

8 0
3 years ago
Use standard enthalpies of formation to calculate Δ H ∘ rxn for each reaction. MISSED THIS? Read Section 7.9; Watch KCV 7.9, IWE
Eva8 [605]

Answer:

Standard Heat of Reaction 1 = -136.2 kJ/mol

Standard Heat of Reaction 2 = -41.166 kJ/mol

Standard Heat of Reaction 3 = -136.07 kJ/mol

Standard Heat of Reaction 4 = 279.448kJ/mol

Explanation:

C₂H₄ (g) + H₂ (g) → C₂H₆ (g)

CO (g) + H₂O (g) → H₂ (g) + CO₂ (g)

3NO₂ (g) + H₂O (l) → 2HNO₃ (aq) + NO (g)

Cr₂O₃ (s) + 3CO (g) → 2Cr (s) + 3CO₂ (g)

The required standard heat of formation for each of the reactants and product above, as obtained from literature is listed below.

C₂H₄ (g), 52.5 kJ/mol

H₂ (g), 0 kJ/mol

C₂H₆ (g), -83.7 kJ/mol

CO (g), -110.525 kJ/mol

H₂O (g), -241.818 kJ/mol

H₂ (g), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

NO₂ (g), 33.2 kJ/mol

H₂O (l), -285.8 kJ/mol

HNO₃ (aq), -206.28 kJ/mol

NO (g), 90.29 kJ/mol

Cr₂O₃ (s), -1128.4 kJ/mol

CO (g), -110.525 kJ/mol

Cr (s), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

Note that

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

C₂H₄ (g) + H₂ (g) → C₂H₆ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (1×-83.7) = -83.7 kJ/mol

ΔH∘(reactants) = (1×52.5) + (1×0) = 52.5 kJ/mol

ΔH∘(rxn) = -83.7 - 52.5 = -136.2 kJ/mol

CO (g) + H₂O (g) → H₂ (g) + CO₂ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (1×0) + (1×-393.509) = -393.509 kJ/mol

ΔH∘(reactants) = (1×-110.525) + (1×-241.818) = -352.343 kJ/mol

ΔH∘(rxn) = -393.509 - (-352.343) = -41.166 kJ/mol

3NO₂ (g) + H₂O (l) → 2HNO₃ (aq) + NO (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (2×-206.28) + (1×90.29) = -322.27 kJ/mol

ΔH∘(reactants) = (3×33.2) + (1×-285.8) = -186.2 kJ/mol

ΔH∘(rxn) = -322.27 - (-186.2) = -136.07 kJ/mol

Cr₂O₃ (s) + 3CO (g) → 2Cr (s) + 3CO₂ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (2×0) + (3×-393.509) = -1,180.527 kJ/mol

ΔH∘(reactants) = (1×-1128.4) + (3×-110.525) = -1,459.975 kJ/mol

ΔH∘(rxn) = -1,180.527 - (-1,459.975) = 279.448 kJ/mol

Hope this Helps!!!

4 0
3 years ago
Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the expe
Anika [276]

Factors that increases reaction rate such as increase in concentration or pressure will reduce reaction time whereas factors that decrease reaction rate such as inhibitors will increase reaction time.

<h3>What are the factors that affect reaction rate?</h3>

Factors that affect reaction rate are those factors which increase or decrease the rate of chemical reaction.

The factors that affect reaction rate include:

  • temperature
  • concentration/pressure
  • catalysts
  • surface area
  • nature of substance

Any factor that increases reaction rate such as increase in concentration or pressure will reduce reaction time whereas factors that decrease reaction rate such as inhibitors will increase reaction time.

Learn more about factors affecting reaction rate at: brainly.com/question/14817541

#SPJ1

6 0
2 years ago
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