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Whitepunk [10]
1 year ago
14

The difference between the calculated voltage (based on standard potentials) and the actual voltage required to cause electrolys

is is called .
Chemistry
1 answer:
Mrrafil [7]1 year ago
5 0

The difference between the calculated voltage (based on standard potentials) and the actual voltage required to cause electrolysis is called overvoltage.

<h3>Electrolysis </h3>

Electrolysis is the technique of causing a chemical change in a substance by passing an electric current through it. The substance either loses or gets an electron during the chemical transition (oxidation or reduction). The procedure is carried out in an electrolytic cell, a device made up of positive and negative electrodes that are kept apart and submerged in a solution with ions that are both positively and negatively charged. The chemical that needs to be converted might either be dissolved in the solution or could form the electrode. The negatively charged electrode (cathode) receives electrical current (i.e., electrons), which travels there and combines with the components of the solution to convert them (reduced).

Learn more about electrolysis here:

brainly.com/question/12054569

#SPJ4

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How is the miscibility of two liquids related to their polarity?
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Answer:

The more polar the liquid, the more likely that it is miscible with water. The polarity of a liquid does not affect its miscibility with water. The less polar the liquid, the more likely that it is miscible with water. The more polar the liquid, the less likely that it is miscible with water.

Explanation:

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Of the following solutions, which has the greatest buffering capacity?
Goshia [24]

Answer:

d. 0.121 M HC2H3O2 and 0.116 M NaC2H3O2

Explanation:

Hello,

In this case, since the pH variation is analyzed via the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[Base]}{[Acid]} )

We can infer that the nearer to 1 the ratio of of the concentration of the base to the concentration of the acid the better the buffering capacity. In such a way, since the sodium acetate is acting as the base and the acetic acid as the acid, we have:

a. \frac{[Base]}{[Acid]}=\frac{0.497M}{0.365M}=1.36

b. \frac{[Base]}{[Acid]}=\frac{0.217M}{0.521M}=0.417

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Therefore, the d. solution has the best buffering capacity.

Regards.

4 0
3 years ago
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