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4 years ago

What is the single replacement reaction for chlorine + aluminum bromide

1 answer:

4 0

Chlorine + aluminium bromide --> aluminium chloride + bromine
Chlorine replaces bromide in AlBr3
3Cl2 + 2AlBr3 ---> 2AlCl3 + 3Br2

Hope it helped!

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Answer the following questions ( image) with the given options.

bagirrra123 [75]

3.Ca(HCO3)2

4. use of Ca(OH)2

3 0

4 years ago

Read 2 more answers

consider the reaction between calcium oxide and carbon dioxide: cao ( s ) + co 2 ( g ) → caco 3 ( s ) a chemist allows 14.4 g of

MakcuM [25]

Answer:

CaO is the limiting reagent

Theoritical yield = 25.71 g

% Yield = 75.44%

Explanation:

1 mole = Molar mass of the substance

Molar Mass of CaO = 56 g/mol

Molar Mass of CaCO3 = 100 g/mol

Molar mass of CO2 = 44 g/mol

The balanced Equation is :

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO reacts with = 1 mole of CO2

56 g of CaO reacts with = 44 g of CO2

1 g of CaO reacts with =

$\frac{44}{56}$

= 0.785 g of CO2

So,

14.4 g of CaO must react with = (14.4 x 0.785) g of CO2

= 11.31 g of CO2

Needed = 11.31 g

Available CO2 = 13.8 g (given)

So CO2 is in excess , hence CaO is the limiting reagent and product will produce from 14.4 g of CaO

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO will produce 1 mole pf CaCO3

56 g of CaO produce = 100 g of CaCO3

1 g of CaO produce =

$\frac{100}{56}$

= 1.785 g of CaCO3

14.4 g of CaO will produce = (1.785 x 14.4) g of CaCO3

= 25.71 g of CaCO3

Theoritical Yield of CaCO3 = 25.71 g

Actual yield = 19.4 g

Percent Yield =

$\frac{Actual\ yield}{Theoritical\ yield}\times 100$

$\frac{19.4}{25.71}\times 100$

= 75.44 %

6 0

3 years ago

** GIVEN THE BRAINLIEST** IF CORRECT!!

Drupady [299]

Answer is: The zooplankton can be used to help control algal growth in some coral communities.

Hypothesis is a suggested explanation for an observable phenomenon.

Steps of the scientific method:

1) ask a question about something that is observed.

2) do background research.

3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested. In this example, does the presence of a certain type of zooplankton inhibited the algae growth

4) test of hypothesis.

5) analyze collected data and draw a conclusion. In this example, the zooplankton can be used to help control algal growth.

5 0

4 years ago

For each mole of glucose (C6H12O6) completely oxidized by cellular respiration, how many moles of CO2 are released in the citric

topjm [15]

Answer:

Step-by-step explanation:

The reactions are:

Glycolysis: 1 glucose ⟶ 2 pyruvate

Link reaction: 2 × [1 pyruvate ⟶ 1 acetyl CoA]

Citric acid cycle: 2 × [1 AcetylCoA ⟶ 2 CO₂]

Now, add the reactions, cancelling species that occur on both sides of the reaction arrow,

1 glucose ⟶ 2 pyruvate

2 pyruvate ⟶ 2 acetyl CoA

2 AcetylCoA ⟶ 4 CO₂

Overall : 1 glucose ⟶ 4 CO₂

For each mole of glucose, four molecules of CO₂ are released in the citric acid cycle.

4 0

3 years ago

Q 13.3: Which of the following is the least stable radical choice? Tertiary radical. B : Allyl radical. C : Secondary radical. D

ss7ja [257]

Answer:

Methyl radical

Explanation:

A radical is any specie that contains an odd number of electrons. We must note that the greater the number of alkyl groups which are attached to a carbon atom that bears the odd electrons, the more the degree of delocalization of the odd electrons and consequently the more stable we expect the free radical to be.

Hence the order of free radical stability is; Methyl < Primary < Secondary < Tertiary. Hence, we can easily see that the methyl radical is the least stable free radical.

3 0

3 years ago