Answer:
1. 2.67 s
2. 0.1 m/s²
Explanation:
1. Determination of the time taken for the penguin to fall.
Height (h) of cliff = 35 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
35 = ½ × 9.8 × t²
35 = 4.9 × t²
Divide both side by 4.9
t² = 35 / 4.9
Take the square root of both side
t = √(35 / 4.9)
t = 2.67 s
Thus, it will take 2.67 s for the penguin to fall onto the head of a napping polar bear.
2. Determination of the acceleration of the penguin.
Initial velocity (u) = 0 m/s.
Final velocity (v) = 2 m/s.
Time (t) = 20 s
Acceleration (a) =?
a = (v – u)/t
a = (2 – 0)/ 20
a = 2 / 20
a = 0.1 m/s²
Thus, the acceleration of the penguin is 0.1 m/s²
Answer:
r = 9521.29
Explanation:
Given:
Gravitational Force = (Fg)
Student Mass 1 = 71 kg (M)
Student Mass 2 = 67kg (m)
Gravitational constant = (G)
r = 9521.29
It works because the paper clip is heavier and more magnetic to the magnet
Fall time machine:
t = √ (2*H/g) = √ (2*40.8 / 9,8) ≈ 2.9 s
Horizontal movement:
S = V₀*t
Speed:
V₀ = S / t = 121 / 2.9 ≈ 41.7 m/s or 150 km/h
The Electron would.
Hope this helps!