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labwork [276]
3 years ago
7

WILL GIVE YOU WHAT EVER YOU WANT JUST HELP ME

Physics
1 answer:
Alona [7]3 years ago
5 0

Answer:

Explanation:

Essential Knowledge

It is essential that the student be able to distinguish between specialized structures that allow protists and fungi to obtain energy and explore their environment.

Protists

Protists are organisms that are classified into the Kingdom Protista. Although there is a lot of variety within the protists, they do share some common characteristics.

● Protists are usually single celled organisms.

● Live in moist environments.

● Vary in the ways they move and obtain energy.

Protists obtain their energy in several ways.

● Animal-like protists ingest or absorb food after capturing or trapping it.

● Plant-like protists produce food through photosynthesis.

● Fungus-like protists obtain their food by external digestion either as decomposers or as parasites.

● Some protists have both autotrophic and heterotrophic characteristi

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Part D
anygoal [31]

Answer: I didn't see a difference because the large ball's vertical displacement and velocity are the same as the small one's.

Explanation:

5 0
3 years ago
A visual display of data or information is a
Artist 52 [7]

A visual display of data or information is called a graph. There are many types of graphs. These can include pie graphs, bar graphs, and many more. Graphs are useful, because they show you visually data which is helpful to many. Hope this helped

4 0
3 years ago
At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . wh
Anna35 [415]

We have the equation for electric field E = kQ/d^{2}

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to d^{2}

So, \frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

E_{1} = 485 N/C

d_{1} = 0.208 cm

d_{2} = 0.620 cm

E_{2} = ?

\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}

E_{2} = \frac{485*0.208^{2}}{0.628^{2}}

E_{2} = 53.20 N/C

7 0
3 years ago
Read 2 more answers
The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a
Andreyy89

Answer:

3.6ft

Explanation:

Using= 2*π*sqrt(L/32)

To solve for L, first move 2*n over:

T/(2*π) = sqrt(L/32)

Next,eliminate the square root by squaring both sides

(T/(2*π))2 = L/32

or

T2/(4π2) = L/32

Lastly, multiply both sides by 32 to yield:

32T2/(4π2) = L

and simplify:

8T²/π²= L

Hence, L(T) = 8T²/π²

But T = 2.1

Pi= 3.14

8(2.1)²/3.14²

35.28/9.85

= 3.6feet

5 0
3 years ago
A machine, modeled as a simple spring-mass system, oscillates in simple harmonic motion. Its acceleration is measured to have an
ANTONII [103]

a=5000\dfrac{mm}{s}=5\dfrac{m}{s}

f=10{Hz}\Longrightarrow t=\dfrac{1}{10}s

a_{max}=\dfrac{50\frac{m}{s}}{\frac{s}{10}}\cdot\dfrac{1}{\sqrt{2}}=\dfrac{50\dfrac{m}{s^2}}{\sqrt{2}}\approx\boxed{35.4\dfrac{m}{s^2}}

Hope this helps.

r3t40

5 0
3 years ago
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