v = initial velocity of launch of the stone = 12 m/s
θ = angle of the velocity from the horizontal = 30
Consider the motion of the stone along the vertical direction taking upward direction as positive and down direction as negative.
v₀ = initial velocity along vertical direction = v Sinθ = 12 Sin30 = 6 m/s
a = acceleration of the stone = - 9.8 m/s²
t = time of travel = 4.8 s
Y = vertical displacement of stone = vertical height of the cliff = ?
using the kinematics equation
Y = v₀ t + (0.5) a t²
inserting the values
Y = 6 (4.8) + (0.5) (- 9.8) (4.8)²
Y = - 84.1 m
hence the height of the cliff comes out to be 84.1 m
If two objects' mass increases, gravitational force pulls them down to the center more strongly because the greater the mass, the stronger the attraction is from the gravitational force from any two objects. An increase in then Earth's mass and increase in a man's mass would make gravitational force pull more strongly on the person because the Earth's gravitational force multiplied from the mass change and the man's greater mass pulls them down more quickly.
Answer:
96.5 km/h
Explanation:
The average velocity of the train is given by:
where
d is the displacement
t is the time taken
For this train, we have:
d = 55 km south (displacement is a vector, so we must also consider the direction)
Substituting into the equation, we find the average velocity:
Answer:
If the height is in metres, the speed is 24.25m/s
Answer:
39 cm North east.
Explanation:
In the attached photo, R is the resultant vector.
Thus, we can obtain the magnitude of the resultant vector of the ant by using the pythagoras theory as illustrated below:
NOTE: R is the Hypothenus ie the longest side
R² = 30² + 25²
R² = 900 + 625
R² = 1525
Take the square root of both side
R = √1525
R = 39.05 ≈ 39 cm
Thus, the magnitude of the resultant vector of the ant is approximately 39 cm north east.