Answer:
8
Explanation:
(8√2)² = x² + x²
8² × √2² = 2x²
64 × 2 = 2x²
128 = 2x²
64 = x²
x = 8
give me brainliest please
Answer:
Potential difference and charge will also increase.
Explanation:
Asking that :
What will happen to the charge and potential difference if the plate area were increased while the plate separation remains unchanged?
The charge is directly proportional to area of the plate. That is, increase in area of the plate of a capacitor will lead to the increase in the charges between the plates.
And since charge is also proportional to the magnitude of potential difference between the plates from the definition of capacitance of a capacitor which says that:
Q = CV
Therefore, increase in the area of the plate will also lead to increase in potential difference between the plates.
Therefore, if the plate area were increased while the plate separation remains unchanged, the charge and potential difference between them will also increase.
Given:
The speed of sound is 340 m/s
Time for the echo is 5.2 s.
Let h = the depth of the canyon.
Because the sound of your voice travels to the bottom of the canyon and back to your ear, the total distance traveled is 2h.
By definition,
distance = velocity * time.
Therefore
2h = (340 m/s)*(5.2 s) = 1768 m
h = 884 m
Answer: The depth is 884 m.
Answer:
1m/s [E]
Explanation:
So for displacement, its saying she went 3000m east and 2000m west. Since these two are in different directions, you would change the sign of one of them to change the direction;
3000m [E] + 2000m [W] = d
3000m [E] - 2000m [E] = d
1000m [E] = d
And its saying the time is 1000 seconds, so using velocity formula:
v = d/t
v=1000m[E] / 1000s
v = 1 m/s [E]
Answer:
A. Using
Pgauge= Pmanometer
And we know that
Pgauge= deta(hpg)
So deta h = Pgauge/density x g
So
= 7.5(6894.76/1psig)/ 13.6*10^3*9.8m/s²)
= 387.9mm
So to find height of pipe connected to the pipe we say
= h -deta h
= 900-387.97mm
=512.02mm
B. We use manometry principle
Pgas+density xg(25*10^3)-PX density{h-(H-0.25)=0
So
Finally Pgas= 6.54psig
