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DiKsa [7]
3 years ago
10

A ramp is used to lift a refrigerator a height of 12 m with a force of 110 N. The ramp is at an angle of 50° to the ground.How m

uch work is being done
Physics
1 answer:
nikitadnepr [17]3 years ago
8 0

Answer:

848.5 J

Explanation:

We are given that

Height,h=12 m

Force,F=110 N

\theta=50^{\circ}

We have to find the work done .

We know that

Work done,W=Fscos\theta

Using the formula

W=110\times 12cos50

W=848.5 J

Hence,the work done=848.5 J

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When you push on the sides of a balloon, the gas inside is ___________.
MrRa [10]

Answer:

the pressure increases.

6 0
4 years ago
A physicist is calibrating a spectrometer that uses a diffraction grating to separate light in order of increasing wavelength (λ
cluponka [151]

Answer:

Explanation:

Given

N=3680 cm^{-1}

therefore slit spacing d=\frac{1}{N}=\frac{1}{3680}=2.717\times 10^{-4}\ cm

since d\sin \theta =n\lambda

for n=1

d\sin \theta =\lambda

Now,at \theta _1=12.9^{\circ},\Rightarrow \lambda _1=6.0657\times 10^{-7}\ m=606.57\ nm

at \theta _2=14.2^{\circ}\Rightarrow \lambda_2=666.5\ nm

at \theta _3=15^{\circ}\Rightarrow \lambda_3=703.21\ nm

5 0
3 years ago
A ramp is used to lift a refrigerator a height of 12 m with a force of 110 N. The ramp is at an angle of 50° to the ground.How m
nikitadnepr [17]

Answer:

848.5 J

Explanation:

We are given that

Height,h=12 m

Force,F=110 N

\theta=50^{\circ}

We have to find the work done .

We know that

Work done,W=Fscos\theta

Using the formula

W=110\times 12cos50

W=848.5 J

Hence,the work done=848.5 J

8 0
3 years ago
Find the acceleration of the blocks when the system is released. The coefficient of kinetic friction is 0.4, and the mass of eac
grin007 [14]

Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

                                     F = ma

mg - mgsinθ - μmgcosθ = (m + m)a

      mg(1 - sinθ - μcosθ) = 2ma

      ½g(1 - sinθ - μcosθ) = a

maximum acceleration is about 2.94 m/s² when θ = 0

acceleration will be zero when θ is greater than about 46.4°

8 0
3 years ago
An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci
VikaD [51]

Answer:

572.3 nm

Explanation:

n_{oil} = refractive index of the oil film = 1.48

t_{oil} = thickness of the oil film = 290 nm

\lambda = wavelength of the dominant color

m = order

Using the equation

2 n_{oil} t_{oil} = (m + 0.5) \lambda

For m = 0

2 (1.48) (290) = (0 + 0.5) \lambda

\lambda = 1716.8 nm

For m = 1

2 (1.48) (290) = (1 + 0.5) \lambda

\lambda = 572.3 nm

For m = 2

2 (1.48) (290) = (2 + 0.5) \lambda

\lambda = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

8 0
4 years ago
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