Electronic signals are converted into a ____ when transmitted through fiber-optic cables.

Two students have fitted their scooters with the same engine. Student A and his

sammy [17]

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

<h3>Force applied by each student</h3>

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

m is mass
a is acceleration

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

Learn more about force here: brainly.com/question/12970081

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3 0

2 years ago

Two long, parallel wires are attracted to each other by a force per unit length of 305 µN/m. One wire carries a current of 25.0

kykrilka [37]

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

$\frac{F}{L} = \frac{kl_1l_2}{d}$

Here,

F = Force

L = Length

k = Coulomb constant

I =Each current

d = Distance

Force of the wire one which is located along the line y to 0.47m is $305*10^{-6}N/m$ then we have

$l_2 = \frac{F}{L} (\frac{d}{kl_1})$

$l_2 = (305*10^{-6}N/m)(\frac{0.470m}{(2*10^{-7})(25A))})$

$l_2 = 28.67A$

Considering the B is zero at

$y = y_1$

$\frac{kI_2}{2\pi y} =\frac{kI_1}{2\pi y_1}$

$\frac{(4\pi*10^{-7})(28.67)}{2\pi (y_1)} = \frac{(4\pi *10^{-7})(25)}{2\pi (0.47-y_1)}$

$y_1 = 0.25m$

Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m

5 0

4 years ago

You and your friends are driving down the road. Your car breaks down. You have to use a 1,210 N force to push the car 201 m to t

Katyanochek1 [597]

Answer:

$2.43\cdot 10^5 J$

Explanation:

Since the force applied is parallel to the displacement of the car, the work done on the car is simply given by:

$W=Fd$

where

F = 1210 N is the force applied on the car

d = 201 m is the displacement of the car

Substituting numbers into the equation, we find:

$W=(1210 N)(201 m)=2.43\cdot 10^5 J$

5 0

4 years ago

A certain refrigerator has a COP of 5.00. When the refrigerator is running, its power input is 500 W. A sample of water of mass

yulyashka [42]

Answer:

t=20s

Explanation:

To solve this problem we must apply the first law of thermodynamics, which indicates that the energy that enters a system is the same that must come out, resulting in the following equation

For this problem we will assume that the water is in a liquid state, since it is a domestic refrigerator

q=m.cp.(T2-T1)

q=heat

m=mass of water =600g=0.6Kg

cp=

specific heat of water=4186J/kgK

T2=temperature in state 2=20°C

T1=temperature in state 1=0°C

solving:

q=(0.6)(4186)(20-0)=50232J

A refrigerator is a device that allows heat to be removed to an enclosure (Qin), by means of the input of an electrical energy (W) and the heat output (Qout), the coefficient of performance COP, allows to know the ratio between the heat removed ( Qin) and the added electrical power (W), the equation for the COP is

$COP=\frac{Qin}{Win}$

To solve this exercise we must know the value of the heat removed to the water (Qin)

solving for Qin

Qin=(COP)(Win)

Qin=(5)(500W)=2500W

finally we remember that the definition of power is the ratio of work over time

w=work

p=power=500w

$P=\frac{W}{t} \\t=\frac{W}{P} \\t=\frac{50232}{2500} \\t=20.09s$

3 0

3 years ago

A 0.200 kg block on a vertical spring with spring constant of 4.65 ✕ 103 N/m is pushed downward, compressing the spring 0.084 m.

vlada-n [284]

Answer:

PEel = PEg

PEel = .5 * k * x^2

= .5 * 4650 * .1^2

= 23.25

PEg= m * g * h

=.2 * 9.81 * h

23.25 = 1.962* h

h = 11.85

4 0

3 years ago