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Ede4ka [16]
3 years ago
15

A teacher wants to demonstrate that unheated water can boil at room temperature in a beaker within a bell jar connected to a vac

-uum pump. However, the vacuum pump is faulty and can reduce pressures only to 15 kPa. Can the teacher use this pump to perform the demonstra-tion successfully? Explain your answer.
Physics
1 answer:
laiz [17]3 years ago
8 0

Answer:

No .

Explanation:

The vapor pressure of water at room temperature is .0313 atom  or 3.13 kPa.

To make a liquid boil, its vapor pressure must be  equal to pressure around it.

So pump must create pressure of 3.13 k Pa or less to make water attain its stage of boiling at room temperature. As the motor  can not produce pressure lesser than 15 k Pa , pump will not be able to make water boil at room temperature.

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As the wavelength increases, the frequency (2 points) Select one:
LiRa [457]
A.
According to the equation: v=λ*f
λ stands for wavelength. wavelength increases, the frequency will decrease. lower frequency deserves low energy.
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4 years ago
Predict the deformation or elongation of a spring that has a constant of elasticity of 400 N/m when a force of 75 N is applied i
morpeh [17]

Answer:

Explanation:

Give that,

Spring constant (k)=40N/m

Force applied =75N

Since the force is applied to the right, we don't know if it is compressing or stretching the spring

So let assume it compress

Using hooke's law

F=-ke

e=-F/k

Then, e=-75/40

e=-1.875m

The deformation is 1.875m.

Let assume it stretch

Using hooke's law

-F=-ke

e=F/k

Then, e=75/40

e=1.875m

The elongation is 1.875m

3 0
3 years ago
If you run 12 m/s for 15 minutes, how far will you go?
vfiekz [6]
10800 m = 10.8 km should be the answer if I am correct
3 0
3 years ago
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Electricity does not commonly occur in nature except in the form of ( hydrocarbons, photosyntheis, lightning, thunder)
horrorfan [7]
Hydrocarbons are compounds of hydrogen and carbon.
Photosynthesis is a process of nutrition in plants.
Thunder is a sound.
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7 0
3 years ago
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Tubby and his twin brother Libby have a combined mass of 200 kg and are zooming along in a 100 kg amusement park bumper car at 1
harkovskaia [24]

Answer: 14.1 m/s

Explanation:

We can solve this with the Conservation of Linear Momentum principle, which states the initial momentum p_{i} (before the elastic collision) must be equal to the final momentum p_{f} (after the elastic collision):

p_{i}=p_{f} (1)

Being:

p_{i}=m_{1}V_{i} + m_{2}U_{i}

p_{f}=m_{1}V_{f} + m_{2}U_{f}

Where:

m_{1}=200 kg +100 kg=300 kg is the combined mass of Tubby and Libby with the car

V_{i}=10 m/s is the velocity of Tubby and Libby with the car before the collision

m_{2}=25 kg + 100 kg=125 kg is the combined mass of Flubby with its car

U_{i}=0 m/s is the velocity of Flubby with the car before the collision

V_{f}=4.12 m/s is the velocity of Tubby and Libby with the car after the collision

U_{f} is the velocity of Flubby with the car after the collision

So, we have the following:

m_{1}V_{i} + m_{2}U_{i}=m_{1}V_{f} + m_{2}U_{f} (2)

Finding U_{f}:

U_{f}=\frac{m_{1}(V_{i}-V_{f})}{m_{2}} (3)

U_{f}=\frac{300 kg(10 m/s-4.12 m/s)}{125 kg} (4)

Finally:

U_{f}=14.1 m/s

8 0
3 years ago
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