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3 years ago

(8k2x2+8k+5)-(3k2x2+5k+1)

Mathematics

2 answers:

MArishka [77]3 years ago

7 0

If you simply if would be: 10k^2+3k+4

Natalka [10]3 years ago

4 0

Answer:

Step-by-step explanation:

=5k^2x^2+3k+4

Hope this helps mark me as brainiest pls

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9000 for 5 years at 4.5% compounded monthly

tatuchka [14]

I think its 9000(1.045)^5. Hope this helps. That equals $11,215.60, or rounded to the nearest dollar, $11,215.

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3 years ago

Andrew claims the initial value and y - intercept are the same thing on a graph. Is he correct?

Agata [3.3K]

Answer:

We conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

Step-by-step explanation:

We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.

In other words, the initial value is the y-value or output of the point at x = 0

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the initial value of the equation y = 2x+1 is: y = 1

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Thus, at y = 1, the line meets the y-axis.

Hence, the initial value of the line is: y = 1

Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the y-intercept of y = 2x+1 is y = 1.

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Therefore, the y-intercept of y = 2x+1 is y = 1.

Conclusion:

Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

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3 years ago

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GenaCL600 [577]

13+B=22
-13. -13
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3 years ago

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Ivenika [448]

Answer: i'm not sure i wrote the problem out correctly but if this helps please give me a thanks!

Step-by-step explanation:

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4 years ago

Suppose f (x )right arrow 250 and g (x )right arrow 0 with g(x)greater than0 as x right arrow 5. Determine ModifyingBelow lim W

Rama09 [41]

Answer:

The limit is $\lim_{x \to 5} \frac{250}{0} = \infty$

Step-by-step explanation:

The equation given are

$f(x) \to 250$

and $g(x) \to 0$

with $g(x) > 0 \ as\ x ---> 5$

The objective is to obtain

$\lim_{x \to 5} \frac{f(x)}{g(x)}$

This mathematically evaluated as

$\lim_{x \to 5} \frac{250}{0}$

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