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pychu [463]
3 years ago
6

Hey you!

Mathematics
1 answer:
Anestetic [448]3 years ago
3 0

1. An angle that measures greater than a right angle measures

2. Acute

3. Obtuse

4. Obtuse

5. An angle that measures the same as a straight line measures

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A family plans to drive their car during their annual vacation. The car can go 340 miles on a tank of gas, which is 16 gallons o
MrMuchimi

Answer:

It would take 86.4 gallons of gas to go 1,836 miles.

Step-by-step explanation:

the situation can be explained by the equation 16x=340, where x is how many miles the car can go in one gallon. divide both sides by 16 to get that answer

x=340/16= 21.25

Now the other problem can be expressed by the equation 21.25y=1836, where y is the amount of gallons it would take to go 1,836 miles.

divide both sides by 21.25 to get the amount of gallons

y= 1836/ 21.25= 86.4.

7 0
3 years ago
Read 2 more answers
Find, correct to the nearest degree, the three angles of the triangle with the given vertices. A(1, 0, −1), B(4, −3, 0), C(1
zavuch27 [327]

Answer:

Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

Step-by-step explanation:

1. First find the length of the vectors  

AB = B-A = (4-1, 3-0, 0-1) = (3, 3, -1)

AC = C-A = (1-1, 4-0, 3-1) = (0, 4, 2)

BC = C-B = (1-4, 4-3, 3-0) = (-3, 1, 3)

2. Find magnitude of the vectors

|AB| = √(3^2+3^2+〖(-1)〗^2 )=√19  

|AC| = √(0^2+4^2+2^2 )=2√5

|BC| = √(〖(-3)〗^2+1^2+3^2 )=√19

3. Find the angles between them

cos θ = (a.b)/(|a||b|) -----> θ = arc cos ((a.b)/(|a||b|))

AB, AC : θ =arc cos (AB.AC)/(|AB||AC|) = arc cos ( (3.0+3.4+ -1.2)/(√19  x 2√5)=  10/(2√95) ) =59.136, which is approximately 59.14°

AB, BC : θ =arc cos (AB.BC)/(|AB||BC|) = arc cos( (3.-3+3.1+ -1.3)/(√19  x √19)=  (-9)/19 ) = 118.27°

Because of the direction of BC is pointing relative to AB this is the angle outside the triangle, and we should find the supplementary angle.

180-118.27 = 61.73°

If we used –(BC) = CB in the formula (just negate the numerator) we would have gotten the correct angle on first try.

The 3rd angle should be what’s left after subtracting from 180°;

180-61.73-59.14 = 59.13 °

You can confirm using the formula again :

AC, BC : θ =arc cos (AC.BC)/(|AC||BC|) = arc cos( (0.-3+4.1+ 2.3)/(√19  x 2√5)=  10/(2√95) = 59.13°

Rounding everything up so they add up to 180 degrees we have Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

7 0
3 years ago
Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7
Lapatulllka [165]

The first equation is y-2x+1=0

y=2x-1 (Equation 1)

The second equation is 4x^{2}+3y^{2}-2xy=7 (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

4x^{2}+3(2x-1)^{2}-2x(2x-1)=7

4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7

by simplifying the given equation,

12x^{2}-10x-4=0

6x^{2}-5x-2=0

Using discriminant formula,

D=b^{2}-4ac

D=25-4 \times 6 \times -2 = 73

Now the formula for solution 'x' of quadratic equation is given by:

x=\frac{-b+\sqrt{D}}{2a}  and  x=\frac{-b-\sqrt{D}}{2a}

x=\frac{5+\sqrt{73}}{12}  and x=\frac{5-\sqrt{73}}{12}

Hence, these are the required solutions.

8 0
3 years ago
(10 points) <br> Solve for x. Assume that the lines which appear to be tangent are tangent
Ganezh [65]

The two tangent lines for each circle are the same length. Set the equations to equal and solve for x.

1. 4x + 3 = 3x +12

Subtract 3x from each side:

x +3 = 12

Subtract 3 from both sides:

x = 9

2. -2 + x = 2x -7

Subtract 2x from both sides:

-2 - x =  -7

Add 2 to each side:

-x = -5

Multiply both sides by -1:

x = 5

8 0
3 years ago
If you substracted 3 frome the exponent in an exponential function , what will happen to the graph​
Mekhanik [1.2K]

Subtracting a value from the exponent shifts the graph to the right.

So if you subtract 3, the graph would shift 3 units to the right.

6 0
3 years ago
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