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faust18 [17]
3 years ago
12

Unpolarized light passes through three polarizing filters. The first one is oriented with a horizontal transmission axis, the se

cond filter has its transmission axis 25.7° from the horizontal, and the third one has a vertical transmission axis. What percent of the light gets through this combination of filters
Physics
1 answer:
sergey [27]3 years ago
4 0

Answer:

7.6 %

Explanation:

As the first polarizer is oriented with a horizontal transmission axis so the light intensity passes through first polarizer is I_1=\frac{I_0}{2}

The second filter has its transmission axis 25.7° from the horizontal so amount if light intensity passes through second polarizer is I_2=I_1cos^225.27^{\circ}=0.812I_1  as I_1=0.5I_0 so I_2=0.812\times 0.5I_0=0.406I_0

Now the third polarizer is has vertical transmission axis so light intensity passes through third polarizer is I_3=I_2cos^2(90^{\circ}-25.7)=0.188I_2  as I_2=0.406I_0  so  I_3=0.188\times 0.406I_0=0.076I_0

\frac{I_3}{I_0}=\frac{0.076I_0}{I_0}=0.076=7.6 % so the 7.6 % of the light intensity passes through filter combination

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<span>F=m(a+g) → F=2.5kg (3.00m/s^2 + 9.8m/s^2) → F=2.5kg (12.8m/s^2) → F=32 N 
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Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

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Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

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v₁ = velocity of the object before the impulse = 18.2 [m/s]

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