A 50.0 kg object is moving at 18.2 m/s when a 200 N force is applied opposite the direction of the objects motion, causing it to
1 answer:
Answer:
t = 1.4[s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 50 [kg]
v = velocity [m/s]
F = force = 200[N]
t = time = [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
where:
m₁ = mass of the object = 50 [kg]
v₁ = velocity of the object before the impulse = 18.2 [m/s]
v₂ = velocity of the object after the impulse = 12.6 [m/s]
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Answer:
speed of a particle = 2.31 × m/s
energy of proton required = 27.77 KeV
energy of electron required = 15.171 eV
Explanation:
given data
magnetic field of magnitude = 0.22 T
electric field of magnitude = 0.51 MV/m
to find out
speed of a particle and energy must protons have to pass through undeflected and energy must electrons have to pass through undeflected
solution
we know that force due to magnetic and electric field is express as
force due to magnetic field B = qvB ..............1
and force due to electric field E = qE .....................2
so without deflection force due to magnetic field = force due to electric field
so here qvB = qE
and V = ...................3
put here value
V =
speed of a particle = 2.31 × m/s
and
now energy of proton required will be here as
energy of proton required = mass of proton ×
put here value
energy of proton required = 1.67 × ×
energy of proton required = 4.45 × J
energy of proton required = 4.45 × J ÷ (1.602 ×
energy of proton required = 27777.777 eV
energy of proton required = 27.77 KeV
and
now we get here energy of electron required that is
energy of electron required = mass of electron ×
put here value
energy of electron required = 9.11 × ×
energy of electron required = 24.305× J
energy of electron required = 24.305 × J ÷ (1.602 ×
energy of electron required = 15.171 eV
Answer:
d = (75 i ^ + 93 j ^ + 27 k ^) m , d2 = (900 i ^ + 1116 j ^ + 324 k ^) m
Explanation:
The two objects are in circular orbit together, therefore with the same angular velocity, after the launch they move with the relative velocity, so we can use the kinematic relation
v = d / t
d = v t
Reduce time to units SI
t = 5 min (60 s / 1 min) = 300 s
X axis
x = vₓ t
x = 0.25 300
x = 75 m
Y axis
y = t
y = 0.31 300
y = 93 m
Z axis
z= t
z = 0.09 300
z = 27 m
d = (75 i ^ + 93 j ^ + 27 k ^) m
For the time of 1 h
t2 = 1 h (3600s / 1 h) = 3600
x2 = 900 m
y2 = 1116 m
z2 = 324 m
d2 = (900 i ^ + 1116 j ^ + 324 k ^) m