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quester [9]
3 years ago
8

When a solution of beryllium sulfate and calcium hydroxide are mixed, what precipitate if any is formed

Chemistry
1 answer:
klasskru [66]3 years ago
5 0

Answer:

CaSO₄ (calcium suflate) is the precipitate formed

Explanation:

We can think the reactants:

BeSO₄ → Beryllium sulfate

Ca(OH)₂ → Calcium hydroxide

The reaction is:

Be₂SO₄  +  Ca(OH)₂  →  CaSO₄ ↓  +  Be(OH)₂

We call it as a double-replacement reaction because two ions exchange places from 2 compounds to form two new compounds.

Sulfates can always make precipitate with the elements from group 2, Ca, Ba and Mg.  

Hydroxides from group 2 are solubles, so we complete states:

BeSO₄ (aq)  +  Ca(OH)₂ (aq)  →  CaSO₄ ↓ (s)  +  Be(OH)₂ (aq)

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HELP.
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Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

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Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

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