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vitfil [10]
3 years ago
6

What is the answer to 9/8= g+1/2

Mathematics
2 answers:
vlada-n [284]3 years ago
7 0
9/8=g+1/2

g=9/8-1/2


g=9/8-4/8

g=5/8 

Decimal Form: 0.625
LUCKY_DIMON [66]3 years ago
6 0
9/8=g+1/2
Making g the subject of the formula
g=9/8-1/2
g=9/8-4/8
g=5/8
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Which inequality correctly orders the numbers -5,-3, and 2 from greatest to least?
lozanna [386]

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Step-by-step explanation:

that is mathematically correct

8 0
3 years ago
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GEOMETRY PROBLEMS PLEASE HELP ME
SIZIF [17.4K]

Answer:

12) The measure of PQR is 36 since both angles MQP (25) and PQR should add up to MQR (61)

13) The graph shows that both angles are congruent so that means:

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2x= x+14

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14) angle ADB and angle BDC since it shows that both angles sum up to 90 degrees (also known as complementary angles)

15) Angles ADE and angle FDE are supplementary because they both add up to 180 degrees (supplementary angles)

16) Angles ADC and FDE are vertical because they are opposite of each other

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7 0
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What is the value of sin A?<br><br> A. 9/12<br><br> B. 12/9<br><br> C. 9/15<br><br> D. 12/15
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3 0
3 years ago
Use the given zero to find the remaining zeros of each function f(x)=2x^4+5x^3+5x^2+20x-12 zero:-2i
frutty [35]

Answer:

1/2, 3

Step-by-step explanation:

This is a pretty involved problem, so I'm going to start by laying out two facts that our going to help us get there.

  1. The Fundamental Theorem of Algebra tells us that any polynomial has <em>as many zeroes as its degree</em>. Our function f(x) has a degree of 4, so we'll have 4 zeroes. Also,
  2. Complex zeroes come in pairs. Specifically, they come in <em>conjugate pairs</em>. If -2i is a zero, 2i must be a zero, too. The "why" is beyond the scope of this response, but this result is called the "complex conjugate root theorem".

In 2., I mentioned that both -2i and 2i must be zeroes of f(x). This means that both x-2i and x+2i are factors of f(x), and furthermore, their product, x^2+4, is <em>also</em> a factor. To see what's left after we factor out that product, we can use polynomial long division to find that

2x^4+5x^3+5x^2+20x-12=(x^2+4)(2x^2+5x-3)

I'll go through to steps to factor that second expression below:

2x^2+5x-3=2x^2+6x-x-3\\=2x(x+3)-(x+3)\\=(2x-1)(x+3)

Solving both of the expressions when f(x) = 0 gets us our final two zeroes:

2x-1=0\\2x=1\\x=1/2

x+3=0\\x=-3

So, the remaining zeroes are 1/2 and 3.

8 0
4 years ago
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