2 years ago

Approximate √12 to the nearest tenth.

Mathematics

2 answers:

Serjik [45]2 years ago

7 0

Answer:

√12 in nearest tenth is 3.5 is the answer

bezimeni [28]2 years ago

3 0

Answer:

3.46

Step-by-step explanation:

since square root of 12 is irrational we get the answer in decimal so we just have to take it to the nearest tenth

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Give the equation of the circle centered at the origin and passing through the point (0,5)

Julli [10]

Answer:

$x^{2} +y^{2}=25$

Step-by-step explanation

The standard equation of a circle centered at origin is $x^{2} +y^{2} =r^{2}$

r = radius of the circle

The circle is passing through the point (0,5)

∴ radius $r=\sqrt{(0-0)^{2}+(5-0)^{2} }$

$r=\sqrt{0+25}$

$r=\sqrt{25}$

$r^{2}=25$

∴ The equation of the circle is

$x^{2} +y^{2} = 25$

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Find the exact value by using a half-angle identity.<br><br> tan seven pi divided by eight

murzikaleks [220]

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Step-by-step explanation:

$\tan(x/2)=\dfrac{1-\cos(x)}{\sin(x)}\\\\\tan\left(\dfrac{1}{2}\cdot\dfrac{7\pi}{4}\right)=\dfrac{1-\cos\dfrac{7\pi}{4}}{\sin\dfrac{7\pi}{4}}=\dfrac{1-\dfrac{1}{\sqrt{2}}}{-\dfrac{1}{\sqrt{2}}}=\boxed{1-\sqrt{2}}$

tan(7π/8) = 1 -√2

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2 years ago

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Fiesta28 [93]

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Step-by-step explanation:

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