I need help !!!!!! !!!!!!!!

A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an

liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

when the angle is 30 degrees

$tan(30) = \frac{6000}{d1}$

$d1 = \frac{6000}{tan(30)}$

$d1 = \frac{6000}{0.577}$

d1 = 10392.3 meters

when the angle is 60 degrees

$tan(60) = \frac{6000}{d2}$

$d2 = \frac{6000}{tan(60)}$

$d2 = \frac{6000}{1.732}\\$

d2 = 3464.1 meters

distance travelled by aircraft in 1 min is

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

Now converting to m/sec

=> $\frac{6928.2}{60}$

=>115.47 m/sec

4 0

3 years ago

Need help asap!!!!!!

Mrac [35]

Answer: x=4

Step-by-step explanation: first you should write it out like it is telling you. put a line and EG is the line and f is in the middle of the two looks kinda like this E F G but they are on a line EG= 25 that means the whole thing equals 25. EF= 2x-6 and FG= 4x+7. when you plug that in it should look like this 25=2x-6+4x+7 then solve.

3 0

3 years ago

This is the pic for the previous question...

Elina [12.6K]

Answer:

Ohh .........................

8 0

3 years ago

If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm

natulia [17]

Answer:

Step-by-step explanation:

This problem is borers on elasticity of materials.

according to Hooke's law, "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."

$F= ke$