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mr Goodwill [35]

3 years ago

8

Rida and Elisa are each paid by the hour rida worked 5 1/2 hours and earned $77 Elisa worked 3 3/4 hours and $60 whose hourly ra

te is greater

2 answers:

allochka39001 [22]3 years ago

5 0

Rida:
5 1/2 :77
5.5 : 77
Divide both sides by 5.5 to get $/hour:
1:14

Elisa:
3 3/4:60
3.75:60
Divide both sides by 3.75 to get $/hour:
1:16

16 is bigger than 14 so Elisa earns more.

DerKrebs [107]3 years ago

4 0

Answer:

Elisa hourly salary is more than Rida's hourly salary

Step-by-step explanation:

Rida worked for $5\dfrac{1}{2}\ hours$ and earned $77

Elisa worked for $3\dfrac{3}{4}\ hours$ and earned $ 60

Rida salary per hour will be = $\dfrac{77}{\dfrac{11}{2}}$

= $ 14

Elisa salary per hour will be = $\dfrac{60}{\dfrac{15}{4}}$

= $ 16

hence, Elisa hourly salary is more than Rida's hourly salary

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Answer:

$P(A) = 0.45$

$P(B) = 0.32$

Step-by-step explanation:

Given

$P(A) > P(B)$

$P(A\ u\ B) = 0.626$

$P(A\ n\ B) = 0.144$

Required

Find P(A) and P(B)

We have that:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$ --- (1)

and

$P(A\ n\ B) = P(A) * P(B)$ --- (2)

The equations become:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$ --- (1)

$0.626 = P(A) + P(B) - 0.144$

Collect like terms

$P(A) + P(B) = 0.626 + 0.144$

$P(A) + P(B) = 0.770$

Make P(A) the subject

$P(A) = 0.770 - P(B)$

$P(A\ n\ B) = P(A) * P(B)$ --- (2)

$0.144 = P(A) * P(B)$

$P(A) * P(B) = 0.144$

Substitute: $P(A) = 0.770 - P(B)$

$[0.770 - P(B)] * P(B) = 0.144$

Open bracket

$0.770P(B) - P(B)^2 = 0.144$

Represent P(B) with x

$0.770x - x^2 = 0.144$

Rewrite as:

$x^2 - 0.770x + 0.144 = 0$

Expand

$x^2 - 0.45x - 0.32x + 0.144 = 0$

Factorize:

$x[x - 0.45] - 0.32[x - 0.45]= 0$

Factor out x - 0.45

$[x - 0.32][x - 0.45]= 0$

Split

$x - 0.32= 0 \ or\ x - 0.45= 0$

Solve for x

$x = 0.32\ or\ x = 0.45$

Recall that:

$P(B) = x$

So, we have:

$P(B) = 0.32 \ or \ P(B) = 0.45$

Recall that:

$P(A) = 0.770 - P(B)$

So, we have:

$P(A) = 0.770 - 0.32 \ or\ P(A) =0.770 - 0.45$

$P(A) = 0.45 \ or\ P(A) =0.32$

Since:

$P(A) > P(B)$

Then:

$P(A) = 0.45$

$P(B) = 0.32$

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