Answer: 1.94 x 10^3 L
Explanation
If the question gives you givens of temperature and volume with no change in pressure, then you must apply Charles Law: V1/T1 = V2/T2, where temperatures must be in Kelvin, K.
To convert °C to K, you add +273 to it.
1.65 x 10^3/ (25+273) = V2/ (77+273)
Cross multiplying to find V2 will give you a volume of ≈ 1,937.9 L
The number of significant figures in the given volume is 3, so therefore your new volume must also be 3 significant figures.
= 1.94 x10^3
Hope this helps :)
Explanation:
Formula to calculate final pressure is as follows.
............... (1)
Since, earlier the tube had no gas therefore, its pressure was zero initially considering temperature remains constant.
So, total number of moles will be as follows.
n = 
As, T and R will be common on both the sides. Hence, they will cancel out from both the sides.
Therefore, putting the given values into equation (1) as follows.
704.88 + 485.0 + 129.96 = 
= 3.18 atm
Therefore, we can conclude that final pressure of the whole system in atm is 3.18 atm.
The answer is <span> D. the periodic table is arranged by the outermost electrons of the elements</span>
Answer:
The correct answer is 0.09 percent.
Explanation:
Based on the given information, the atomic radius is 2 × 10⁻¹⁰ m. Now the atomic volume can be determined by using the formula, 4/3πr³. by putting the values we get,
v = 4/3πr³ = 4/3π(2×10⁻¹⁰ m)³
v = 3.35 × 10⁻²⁹ m³
The no. of atoms present in one mole of xenon is 6.02 × 10²³ atoms. Therefore, the total atomic volume will be,
Va = 6.02 × 10²³ × 3.35 × 10⁻²⁹
Va = 2.02 × 10⁻⁵ m³
The %age of total volume occupied can be determined by dividing the total atomic volume with the volume under STP. Under STP, the volume is 22.4 m³ or 2.24 × 10⁻² m³.
Va/V = 2.02 × 10⁻⁵ m³ / 2.24 × 10⁻² m³
= 9.02 × 10⁻⁴ or 0.09 %
