Answer:
RbH(s)+ H2O(l) → RbOH + H2
Explanation:
The reaction is;
RbH(s)+ H2O(l) → Product
From Ahmad's statement, we know that the product of he reaction is going to be an Hydroxide (-OH) and hydrogen gas (H2)
So we have;
RbH(s)+ H2O(l) → RbOH + H2
Hey there!:
Number of moles = ( number of atoms / 6.023*10²³ atoms )
given number of atoms = 5.03*10²⁴
Therefore:
Number of moles B = 5.03*10²⁴ / 6.023*10²³
Number of moles B = 8.35 moles
Hope that helps!
Answer:
Mass = 47.04 g
Volume = 23.94 L
Solution:
The equation for given reaction is as follow,
BaCO₃ + 2 HNO₃ → Ba(NO₃)₂ + CO₂ + H₂O
According to this equation,
197.34 g (1 mole) BaCO₃ produces = 44 g (1 mole) of CO₂
So,
211 g of BaCO₃ will produce = X g of CO₂
Solving for X,
X = (211 g × 44 g) ÷ 197.34 g
X = 47.04 g of CO₂
As we know,
44 g (1 mole) CO₂ at STP occupies = 22.4 L volume
So,
47.04 g of CO₂ will occupy = X L of Volume
Solving for X,
X = (47.04 g × 22.4 L) ÷ 44 g
X = 23.94 L Volume
Answer:
The answer to your question is the second option
Explanation:
Reaction
Al₂(SO₄)₃ + KOH ⇒ Al(OH)₃ + K₂SO₄
Process
1.- Check if the reaction is already balanced
Reactants Elements Products
2 Aluminum 1
3 Sulfur 1
13 Oxygen 7
1 Potassium 2
1 Hydrogen 3
The reaction is unbalanced
2.- Balance the reaction
1Al₂(SO₄)₃ + 6KOH ⇒ 2Al(OH)₃ + 3K₂SO₄
Reactants Elements Products
2 Aluminum 2
3 Sulfur 3
18 Oxygen 18
6 Potassium 6
6 Hydrogen 6
Now the reaction is balanced. The coefficients are 1, 6, 2, 3.
Answer:
The given molecules are SO2 and BrF5.
Explanation:
Consider the molecule SO2:
The central atom is S.
The number of domains on S in this molecule is three.
Domain geometry is trigonal planar.
But there is a lone pair on the central atom.
So, according to VSEPR theory,
the molecular geometry becomes bent or V-shape.
Hybridization on the central atom is
.
Consider the molecule BrF5:
The central atom is Br.
The number of domains on the central atom is six.
Domain geometry is octahedral.
But the central atom has a lone pair of electrons.
So, the molecular geometry becomes square pyramidal.
The hybridization of the central atom is 
.
The shapes of SO2 and BrF5 are shown below:
