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qwelly [4]
3 years ago
8

Atomic energy is the energy _____. in the nucleus of an atom of electrons and their shells in chemical bonds of elements and com

pounds
Chemistry
2 answers:
ddd [48]3 years ago
7 0

Answer:

The correct statement to fill the blank would be the first option. Atomic energy is the energy in the nucleus of an atom of electrons and their shells. From the word atomic itself, we can say that this energy is energy within and carried by the atoms.

ivolga24 [154]3 years ago
6 0
The correct statement to fill the blank would be the first option. Atomic energy is the energy in the nucleus of an atom of electrons and their shells. From the word atomic itself, we can say that this energy is energy within and carried by the atoms.
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most radioactive atoms “spontaneously” decay to a more stable form. where does the “additional” energy go once the atoms have de
blsea [12.9K]

When most radioactive atoms “spontaneously” decay to a more stable form the “additional” energy is converted to radiation with the emission of radioactive particles.

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous decay of the nucleus of an atom with the emission of radiation and nuclear particles.

Elements that spontaneously decay are called radioactive elements.

When these radioactive elements decay, they form more stable isotopes or elements.

The spontaneous decay of atoms of radioactive elements is in order for the nucleus of the atom to become stable and non-radioactive.

Learn more about radioactivity at:

brainly.com/question/26626062

#SPJ1

4 0
1 year ago
What is the name of Pb(NO3)2? Explain how you determined the bond type and the steps you used to determine the naming convention
Elena L [17]

Answer: Lead(II) nitrate but idk the rest

Explanation:

5 0
3 years ago
Calculate the second volumes. <br> 7.03 Liters at 31 C and 111 Torr to STP
DIA [1.3K]

The second volume :    V₂= 0.922 L

<h3> Further explanation </h3><h3>Given </h3>

7.03 Liters at 31 C and 111 Torr

Required

The second volume

Solution

T₁ = 31 + 273 = 304 K

P₁ = 111 torr = 0,146 atm

V₁ = 7.03 L

At STP :  

P₂ = 1 atm

T₂ = 273 K

Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

Input the value :

0.146 x 7.03 / 304 = 1 x V₂/273

V₂= 0.922 L

4 0
3 years ago
How many parts does CsF ( Cesium Fluoride ) have?
san4es73 [151]
Good luck on this one brp
7 0
3 years ago
Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th
artcher [175]

Answer:

The <u>equilibrium constant</u> is:

              k_c=0.0030M^{-2}

Explanation:

The correct equation is:

  •   N₂(g)    +    3H₂(g)    ⇄    2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

         k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}

Substituting:

        k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}

         k_c=0.0030M^{-2}

6 0
3 years ago
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