Molality is defined as the number of moles of solute in 1 kg of solvent.
since density and volume has been given we can calculate the mass of water
mass = density x volume
mass = 1.00 g/mL x 1620 mL = 1620 g
number of moles of glucose - 257 g / 180 g/mol = 1.43 mol
number of moles of glucose in 1620 g - 1.43 mol
therefore number of moles in 1000 g - 1.43 mol / 1.620 kg = 0.883 mol/kg
therefore molality is 0.883 mol/kg
Hydrogen molecule is a molecule that releases the most energy when forming its bonds as compared to other molecules.
<h3>What bond needs more energy?</h3>
We know that H-H bond energy is 432 kJ mol-1, CI - CI bond energy is 239kJ mol-1 and Br-Br bond energy is 193 kJ mol-1 so from this data we can conclude that more energy is required to break the bond between hydrogen atom.
Learn more about bond here: brainly.com/question/25596583
Given:
Concentration 1 = 100.0 ml Concentration 2 = ?
Volume 1 = 0.100 M KCL Volume 2= 0.500 M KCL
Find Concentration 2
To get the concentration 2, follow this formula
C1V1 = C2V2
Solution
(100.0 ml) (0.100 m kcl) = (X ml) (0.500 m kcl)
transfer the volume 2 to the left side
(100.0 ml) (0.100 m kcl) = X ml
---------------------------------
0.500 m kcl
10.00ml / m kcl = Xml
-------------------- cancel the m kcl to let the ml be the remaining variable
0.500 m kcl
20.0 ml = x ml
So you will need 20.0 ml of 0.500 m kcl to made the solution of 100.0 ml of 0.100 m kcl
if solvation releases more energy than is consumed during dissolute, the solution formation is favored and the solute is soluble in the solvent.many inter molecular forces can contribute to solvation, including hydrogen bonding, dipole -dipole forces and van der walls forces
Answer:
Explanation:
Given: 19 L of oxygen gas
To find: Number of moles in 19 L of oxygen gas
Solution:
In International System of Units, the mole is the unit of measurement for amount of substance. A mole of a mole of particles is defined as exactly 6.02214076×10²³ particles. Particles may be atoms, molecules, ions, or electrons.
As 1 mole = 22.4 L, 1 L = 1/22.4 mole
So, 
