The balanced chemical formula should be Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4
Therefore the coefficient of Al(OH)3 is 2!
Hope that helps :)
ΔG⁰ = ΔH⁰ - T ΔS⁰
ΔG⁰ : Standard free energy of formation of acetylene
ΔH⁰ : Standard enthalpy of formation (226.7 kJ/mol)
ΔS⁰ : Standard entropy change (58.8 J / K. mol)
T : Temperature 25°C = 298 K (room temperature)
ΔG⁰ = 226.7 - (298 x 58.8 x 10⁻³) = 209.2 kJ /mol
Answer:
Base on the question , an acid and a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution.
Explanation:
Acids are substances that dissolves in water to produce hydrogen ion(H⁺) while base are substances that dissolves in water to produce hydroxide ion (OH⁻).
The chemical reaction between an acid and a base solution is known as a neutralization reaction. The reaction between these 2 compounds will produce salt and water. An acid solution will react with a base solution to form salt and water. An example of this kind of reaction is between HCl (Hydrochloric acid) and NaOH(sodium hydroxide).
HCl + NaOH → NaCl + H₂O . The product form here is sodium chloride(salt) and water
Base on the question , an acid and a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution. Note that the other product which is water has been evaporated and we are left with only salt solution.
Answer:
The correct option is: b. has a downward projection (on the opposite side from the terminal CH₂OH group).
Explanation:
The Haworth Projection depicts the three-dimensional cyclic structure of the monosaccharides.
The monosaccharide, D-glucose predominantly exists in the pyranose form and is known as D-glucopyranose. The D-glucopyranose has two anomeric forms: α- and the β- form and the carbon-1 (C-1 ) is known as the anomeric carbon.
<u>In the Haworth projection of α-D-glucopyranose</u>, the <u>hydroxyl group of anomeric carbon is projected in the downward direction</u>. Whereas, the <u>terminal CH₂OH group on the carbon-5 (C-5), is projected in the upward direction.</u> Therefore, they are on the <u>opposite sides of the plane of ring</u>.
Answer:
The answer it's A. transesterification
