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dalvyx [7]
3 years ago
10

A puppy weighing 3 kilograms races through the dog park. if she slows from a speed of 2 meters/second to 1 meter/second, what wi

ll happen to her kinetic energy? use the kinetic energy equation.
a.her kinetic energy decreases to 1.5 j
b.her kinetic energy increases to 1.5 j
c.her kinetic energy remains unchanged
d.her kinetic energy decreases to 1 j.
Physics
2 answers:
Ne4ueva [31]3 years ago
6 0
Your answer is A. If velocity decreases, your kinetic energy would also decrease.
sdas [7]3 years ago
5 0

Answer:The correct answer is option (a).

Explanation:

Mass of the puppy,m = 3 kg

Kinetic energy of the puppy when it was running with speed of 2 m/s:

K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 3kg\times (2 m/s)^2=6 Joules

Kinetic energy of the puppy when it was running with speed of 1 m/s:

K.E'=\frac{1}{2}mv^2=\frac{1}{2}\times 3kg\times (1 m/s)^2=1.5 Joules

When the puppy was running at the speed f 1 m/s her kinetic energy reduced to 1.5 Joules.

Hence, correct answer is option (a).

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There are none on the list you included with your question.

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20.7 s

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3 years ago
A package is pushed across the floor a distance of 90 feet by exerting a force of 32 lbs downward at an angle of 24 ∘ with the h
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Answer:

2632 foot-pound

Explanation:

Work done: Work is said to be done when ever a force moves a body through a given distance. The S.I unit of force is Newton (N).

From the question,

The expression for work done is given as,

W = Fdcos∅......................... Equation 1

Where W = work done, F = force, d = distance, ∅ = angle between the force and the horizontal.

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substitute into equation 1

W = 32×90×cos24

W = 2880(0.914)

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3 years ago
Metal sphere A is hung from the ceiling by a long, thin string and given a positive charge. An identical sphere B is suspended n
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A decreases while B increases because the equilebrium only reacts to different sphers of this substance.

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A man pushes a lawn mower on a level lawn with a force of 186.5 N. If 3.8% of this
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Explanation:

The force is 186.5 N.  3.8% of the force is directed downward.  So the vertical component of the force is:

Fᵧ = 0.038 (186.5 N)

Fᵧ = 7.087 N

The horizontal component is found with Pythagorean theorem:

F² = Fₓ² + Fᵧ²

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