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trasher [3.6K]
3 years ago
12

Which is the graph of g(x)=10/x

Mathematics
2 answers:
Ber [7]3 years ago
6 0

Answer:

The third option is correct.

Step-by-step explanation:

garri49 [273]3 years ago
4 0

Answer:

We have been given equation as g\left(x\right)=\frac{10}{x}.

Now we need to graph the given equation g\left(x\right)=\frac{10}{x}..

Clearly it is not linear as equation is not of the form y=mx+b. So we need to find some points on given equation g\left(x\right)=\frac{10}{x}. by plugging some random values of x like -5,-3,1,... etc.

for x=-5, we get:

g\left(x\right)=\frac{10}{x}

g\left(-5\right)=\frac{10}{-5}=-2.

Hence first point is at (-5,-2). Similarly we can find more points and graph those points.

x can't be 0 as division by 0 is not defined so it will have vertical asymptote at x=0.

Since degree of numerator is less than degree of denominator so y=0 will be horizontal asymptote.

Now join those points by a curved line to get final graph.

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Solve for x.* (4x + 7)° (6x + 3)° Sign​
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3 years ago
Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

-2(-2C-1) + C = 2  

simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

7 0
3 years ago
Read 2 more answers
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Step-by-step explanation:

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<u>Step-by-step explanation:</u>

When two sides of a triangle are congruent, it is an isosceles triangle.

When three sides of a triangle are congruent, it is an equilateral triangle.

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