All categories

2 years ago

11c+7c-13c=115 whats the value of c?

Mathematics

1 answer:

Degger [83]2 years ago

7 0

Simplify both sides of the equation

11c+7c -13c = 115

Simplify

5c= 115

Divide both sides by 5

5c/5 = 115/5

c = 23

I hope that's help !

You might be interested in

If f(x) = -x + 5 and g(x) = x^2, what is (g*f)(-1)

sasho [114]

Answer:

Step-by-step explanation:

(g × f)(x) = g(x) × f(x) = x²(- x + 5)

To evaluate (g × f)(- 1) substitute x = - 1 into the product

x²(- x + 5)

= (- 1)²(- (- 1) + 5)

= 1(1 + 5)

= 1 × 6 = 6

5 0

3 years ago

The function p(x) = −2000x2 + 18000x − 15000 models the monthly profit P of a smoothie company, where x represents the price per

ohaa [14]

Answer:

Step-by-step explanation:

Givem the profit function

p(x) = −2000x2 + 18000x − 15000

We are to generate the price range that will generate a monthly profit of at least $25,000

Substitute into the function we have;

25000 = −2000x2 + 18000x − 15000

Divide through by 1000

25 = -2x²+18x-15

Rearrange

-2x²+18x-15-25 = 0

2x²-18x+40 = 0

Divide through by 2

x²-9x+20 = 0

Factorize

x²-5x-4x+20 = 0

x(x-5)-4(x-5) = 0

x-4 = 0 and x-5 = 0

x = 4 and x = 5

Hence the price range that will generate a monthly profit of at least $25,000 is between $4 and $5 inclusive

8 0

2 years ago

Help fast I need real answers thanks

BaLLatris [955]

What is the question?

4 0

2 years ago

Read 2 more answers

Type the correct answers out, thank you - 20 POINTS

nadezda [96]

AB and BC form a right angle at their point of intersection. This means AB is perpendicular to BC.

We are given the coordinates of points A and B, using which we can find the equation of the line for AB.

Slope of AB will be:

$m= \frac{-1-1}{14-2}=-1/6$

Using this slope and the point (2,1) we can write the equation for AB as:

$y-1= \frac{-1}{6}(x-2) \\ \\ 
y= -\frac{1}{6}x+ \frac{1}{3}+1 \\ \\ 
y=-\frac{1}{6}x+ \frac{4}{3} 
$

The above equation is in slope intercept form. Thus the y-intercept of AB is 4/3.

Slope of AB is -1/6, so slope of BC would be 6. Using the slope 6 and coordinates of the point B, we can write the equation of BC as:

y - 1 = 6(x - 2)
y = 6x - 12 + 1
y = 6x - 11

Point C lies on the line y = 6x - 11. So if the y-coordinate of C is 13, we can write:

13 = 6x - 11
24 = 6x
x = 4

The x-coordinate of point C will be 4.

Therefore, the answers in correct order are:

4/3 , 6, -11, 4

8 0

2 years ago

Fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5

liubo4ka [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we know that the solution of the following equation

$ax^2+bx+c=0$

are

$\dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \ \text{ when } \Delta=b^2-4ac \geq 0$

<em>I would suggest that you try to apply this formula first and check the solution only after you try.</em>

Let's apply it in this case, we have:

$a=4\sqrt{5} \\ \\ b=-24 \\ \\ c= -9\sqrt{5}$

$\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ \sqrt{\Delta}=36 \ \text{ and the solutions are } \\ \\ \\ x_1=\dfrac{24-36}{8\sqrt{5}}=\dfrac{-12}{8\sqrt{5}}=\boxed{\dfrac{-3}{2\sqrt{5}}} \\ \\x_2=\dfrac{24+36}{8\sqrt{5}}=\dfrac{60}{8\sqrt{5}}=\boxed{\dfrac{15}{2\sqrt{5}}}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago