Ask question

Ask question

All categories

4 years ago

13

Paul is given assistance with finding a job and an apartment, and learning to correctly take his medications. Paul is most likel

y
receiving
O A. social therapy.
O B. insight therapy.
O C.family therapy.
O D. milieu therapy.

1 answer:

o-na [289]4 years ago

6 0

The answer is B. Insight therapy

You might be interested in

2. Why was it important to examine both the color and the streak of your minerals? Think about streak and explain why it’s calle

horrorfan [7]

<span>Some minerals might have similar color, but different streaks. Others might have the same streak color, but different colors</span>

3 0

3 years ago

evablogger [386]

The answer is a bc electric is fast

7 0

4 years ago

Read 2 more answers

A soccer ball at rest is kicked and rolls horizontally for 4 seconds with an acceleration of 2 m/s2. which

frosja888 [35]

Answer:

bdhjcbudd

Explanation:

djhchjdbcj

6 0

3 years ago

Witch of the following best describes the forms of electromagnetic waves produced by sunlight ?

zubka84 [21]

Answer:

A: Sunlight contains ultraviolet waves only.

Explanation:

Hopefully this helps!

6 0

3 years ago

Read 2 more answers

The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 1017 m away from you and 6 ×

vagabundo [1.1K]

Answer:

a)It is NOT possible using this telescope, to see the two stars as separate stars

b) $d_{min} =28.466m$

Explanation:

From the question we are told that:

Diameter of lens, $d = 25 cm \approx 0.25 m$

Distance from both star $D_f= 2*10^{17} m$

Distance between both stars $D_b= 6*10^9 m$

Wavelength of light $\lambda =700 nm \approx 700*10^-9 m$

Generally the equation for angle subtended by the two stars at the lens is mathematically given by

$\theta=\frac{D_f}{D_b}$

$\theta=\frac{6*10^9}{2*10^{17}}$

$\theta=3.0*10^{-8} rad$

Generally the equation for minimum angular separation of two object is mathematically given by

$\theta_{min} = 1.22*\lambda/d$

$\theta_{min}= \frac{1.22*700*10^-9}{0.25}$

$\theta_{min}= 3.416*10^-^6 rad$

Therefore

$\theta < \theta_{min}$

$3.0*10^{-8} rad< 3.416*10^-^6 rad$

It is NOT possible using this telescope, to see the two stars as separate stars

b)

Generally the equation for minimum diameter of the lens is mathematically given by

$d_{min} =\frac{ 1.22*\lambda}{\theta}$

$d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}$

$d_{min} =28.466m$

3 0

3 years ago