Answer:
a) The potential energy in the system is greatest at X.
Explanation:
Let be X the point where a ball rests at the top of a hill. By applying the Principle of Energy Conservation, the total energy in the physical system remains constant and gravitational potential energy at the top of the hill is equal to the sum of kinetic energy, a lower gravitational energy and dissipated work due to nonconservative forces (friction, dragging).

Conclusions are showed as follows:
a) The potential energy in the system is greatest at X.
b) The kinetic energy is the lowest at X and Z.
c) Total energy remains constant as the ball moves from X to Y.
Hence, the correct answer is A.
D. lost an electron
because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration
Q is a concave mirror.
Explanation:
The image formed by a concave mirror is observed to be virtual, erect and larger than the object.
Answer:
2
Explanation:
Step 1: RxN
4Al + 3O₂ → Al₂O₃
Step 2: Balance RxN
We have 4 Al's and 6 O₂'s on the reactant side.
We need the same number of Al's and O₂'s on the product side.
4Al + 3O₂ → 2Al₂O₃
The phases of mitosis in order from first to last are: Interphase, prophase, metaphase, anaphase, and telophase & cytokinesis.