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This is a 2-part motion.
Part 1 of the motion:
Applying equations of motion;
u = 14.4 m/s, s = 78.8 m, t = 9.92 s
s = ut+1/2at^2
78.8 = 14.4*9.92 + 1/2*a*9.92^2
78.8 = 142.848 + 49.2032a
a = (78.8-142.848)/49.2032 = -1.3 m/s^2 (negative sign indicates a deceleration).
Now,
v = u+at
v = 14.4 -1.3*9.92 = 1.49 m/s
Part 2 of the motion:
Final speed in first motion becomes initial velocity in this second motion.
u = 1.49 m/s, a = 1.83 m/s^2, t = 4.50 s
Now,
v = u + at
Then,
v = 1.49 + 1.83*4.50 = 9.72 m/s
The final speed is 9.72 m/s
Electrospray ionization mass spectroscopy often results in analyte molecules fragmenting
FALSE
<u>Electrospray ionization mass spectroscopy</u>
It is a technique using electrospray to generate ions for mass spectrometry by applying high voltage to the liquid.
Electrospray ionization is a soft ionization technique.
It is used for production of gas phase ions.
The process of Electrospray ionization mass spectroscopy
1. dispersal of a fine spray charge droplets
2. solvent evaporation
3. ion ejection from highly charged droplets
To know more about Electrospray ionization mass spectroscopy
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Answer:
E = 1000 x
Explanation:
The electric potential and the electric field are related by the formula
dV = - E . dx
Bold represents vectors.
The point represents the scalar product, in this case we calculate the electric field in the x-axis and the potential is also in this axis so the scalar product is reduced to the algebraic product
E = dV /dx
Let's make the derivative
E = - 2ax
Let's replace the values
E = -2 (-500) x
E = 1000 x