Question

A paintball is fired horizontally from a tower 45 m above the ground. If the paintball gun fires at 90 m/s… How long does it take for the paintball to hit the ground? How far away from the tower will the paintball land?

Answer 1

Answer:

The time taken for the paint ball to hit the ground is $t = 2.143 \ s$

The distance of the landing point from the tower is $d = 192.86 \ m$

Explanation:

From the question we are told that

   The height of the tower is $h = 45 \ m$

    The speed of the paintball in the horizontal direction is  $v_x = 90 \ m/s$

Generally from kinematic equation we have that

      $h = ut + \frac{1}{2} at^2$

Here u is the initial  velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally

         a is equivalent to $g = 9.8\ m/s^2$

        t is the time taken for the paintball to hit the ground

   So    

       $45 = 0* t + \frac{1}{2} 9.8 * t^2$

=>    $t = 2.143 \ s$

Generally the distance of its landing position from the tower is

         $d = v * t$

=>      $d = 90 * 2.143$

=>    $d = 192.86 \ m$