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4 years ago

What is the degree of the polynomial below?

Mathematics

2 answers:

marusya05 [52]4 years ago

7 0

I think it’s D hope this helps

Bogdan [553]4 years ago

6 0

I think its d) 4 im not sure tho

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What is the side length of a cube with a volume of 0.216 m3?

aksik [14]

｡☆✼★ ━━━━━━━━━━━━━━━ ☾

Cube root 0.216 to get your answer

(Note: This makes sense if you know the volume of a cube is the same value multiplied together 3 times)

The answer is option A 0.6 m

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6 0

4 years ago

Write the equation of the line in slope intercept form that passes through the point (6,-2) and is parallel to the line y = -3x

harina [27]

Answer:

For a line to be parallel it must have the same slope. So the slope of the new equation is 6.

The slope intercept form is y=mx+b. And we have a point (3,-5). Plug in what we know....

-5=6(3)+b

Solve for b (the y-intercept)

b= -23

Therefore.... y=6x-23

??? does that help????

3 0

3 years ago

A substance with a half life is decaying exponentially. If there are initially 12 grams of the substance and after 70 minutes th

77julia77 [94]

Answer: 233 min

Step-by-step explanation:

This problem can be solved by the following equation:

$A=A_{o} e^{-kt}$ (1)

Where:

$A=7 g$ is the quantity left after time $t$

$A_{o}=12 g$ is the initial quantity

$t=70 min$ is the time elapsed

$k$ is the constant of decay for the material

So, firstly we need to find the value of $k$ from (1) in order to move to the next part of the problem:

$\frac{A}{A_{o}}=e^{-kt}$ (2)

Applying natural logarithm on both sides of the equation:

$ln(\frac{A}{A_{o}})=ln(e^{-kt})$ (3)

$ln(\frac{A}{A_{o}})=-kt$ (4)

$k=-\frac{ln(\frac{A}{A_{o}})}{t}$ (5)

$k=-\frac{ln(\frac{7 g}{12 g})}{70 min}$ (6)

$k=0.00769995 min^{-1}$ (7) Now that we have the value of $k$ we can solve the other part of this problem: Find the time $t$ for $A=2 g$ .

In this case we need to isolate $t$ from (1):

$t=-\frac{ln(\frac{A}{A_{o}})}{k}$ (8)

$t=-\frac{ln(\frac{2 g}{12 g})}{0.00769995 min^{-1}}$ (9)

Finally:

$t=232.697 min \approx 233 min$

5 0

3 years ago

Calculate δe, if q= 0.769 kj and w= -860 j .

Andreyy89

<span>Best Answer: 1) Q is positive therefore the process is endothermic. .769kj+-.810kj=-.041kj 2) Heat is released meaning it is exothermic. -66.9kj+45=-21.9kj 3) 7.29kj. Endothermic.</span>

7 0

3 years ago

7 people went to dinner. The total

jarptica [38.1K]

Answer:

Step-by-step explanation:

come on this is simple division, thx for the points though

7 0

3 years ago

Read 2 more answers