The magnitude of each vector is the Pythagorean sum of its components.
a. |v1| = √(2² + (-6)²) = √40 = 2√10
|v2| = √((-4)² + 7²) = √65
b. To make each vector into a unit vector, divide each component by the vector's magnitude.
u1 = v1/|v1| = (2/(2√10), -6/(2√10))
u1 = (√10/10, -3√10/10)
u2 = v2/|v2| = (-4/√65, 7/√65)
u2 = (-4√65/65, 7√65/65)
B is the correct answer
hope this helps
Answer:
36/52 or 9/13
Step-by-step explanation:
Ace-9 for all suits; Diamond, Hearts, Spades and Clubs
\left[A \right] = \left[ \frac{ - \left( 5 - 3\,x - 2\,x^{2} - 2\,x^{3}\right) }{-1-x}\right][A]=[−1−x−(5−3x−2x2−2x3)] I hope helping this answer
